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Calculate the molecular mass of caustic potash-A. $K_2$OH = 95 $g{mol}^{-1}$B. KOH = 56 $g{mol}^{-1}$C. K(OH$)_2$ = 73 $g{mol}^{-1}$D. KOH = 58 $g{mol}^{-1}$

Last updated date: 09th Aug 2024
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: Hint: The molecular mass of caustic potash or potassium hydroxide (KOH) is found by knowing the molar masses of the elements.

Complete step-by-step solution -

From the periodic table we can find that the molar mass of potassium or K is 39.098 g/mole.
Similarly, the molar mass of O is found to be 15.999 g/mole from the periodic table.
And the molar mass of H is found to be 1.00784 g/mole.
We know the formula of caustic potash is KOH.
The molecular weight of caustic potash or KOH (potassium hydroxide) is = Molar mass of K + Molar mass of O + Molar mass of $H{\text{ }} = {\text{ }}\left( {39.098{\text{ }} + {\text{ }}15.999{\text{ }} + {\text{ }}1.00784} \right){\text{ }}g/mole{\text{ }} = {\text{ }}56.10484{\text{ }}g/mole$
$\approx \;56{\text{ }}g/mole$
Therefore, we conclude that Option B is the correct answer.