Question

${{C}_{3}}{{H}_{8}}+5{{O}_{2}}\to 3C{{O}_{2}}+4{{H}_{2}}O$, how much propane is needed to react with 6.2 moles of oxygen?

Answer 1

Hint: Heating of organic compounds in the presence of oxygen is called combustion reaction. From the given balanced chemical reaction we can say that one mole of propane reacts with five moles of oxygen in combustion reaction.

Complete step by step answer:
- In the question it is asked to calculate how much propane is required to react with 60.2 moles of oxygen.
- The given balanced chemical reaction is as follows.
${{C}_{3}}{{H}_{8}}+5{{O}_{2}}\to 3C{{O}_{2}}+4{{H}_{2}}O$
- From the above chemical reaction we can say that one mole of propane reacts with 5 moles of oxygen to get 3 moles of carbon dioxide and four moles of water.
- Means for the complete combustion reaction of one mole of propane there is a need of 5 moles of oxygen.
- Which means I mole of oxygen reacts with 0.2 moles of propane.
- In the question it is asked to calculate how much propane is required to react with 6.2 moles of oxygen.
- Therefore the amount of propane required to react with 6.2 moles of oxygen = (6.2) (0.2) = 1.24 moles.
- So, 1.24 moles of propane is required to react with 6.2 moles of oxygen.

Note: From the balanced chemical reaction only we will get the information about how many moles of one reactant is going to react with how many moles of other reactant and how many moles of the products are going to form.