Bhushan counted to 60 using multiples of 6. Which statement is true about multiples of 6?
A) They are all odd numbers.
B) They all have 6 in the one’s place
C) They can all be evenly divided by 3
D) They can all be evenly divided by 12
Answer
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Hint: Simply, all the multiples of 6 will also be divisible by 6. Therefore, we can use the divisibility rule for 6 to observe the properties of its multiples.
As 6 = 2 X 3, all the multiples of 6 are divisible by 2 as well as 3
Complete step-by-step answer:
Divisibility rule for 6:
Since 6 = 2 X 3, all the numbers divisible by 6 are also divisible by 2 and 3
For 2: the digit at one's place should be even.
For 3: the sum of all digits should be divisible by three
Checking the options:
A) states that the multiples are all odd numbers which is wrong as the numbers divisible by 2 will always be even
B) states that all the multiples have 6 in the one’s place which can be held for the divisibility by 2 but not always in case of 3 as the sum of the rest of the numbers might not be divisible by 3.
C) states that the multiples can be evenly divided by 3 which can be held for both 2 and 3 as the numbers divisible by 2 are always even.
D) states that the multiples can be evenly divided by 12 which cannot be held true for all the multiples as 6 X 3 = 18 and is not divisible by 12
So, the correct answer is “Option C”.
Note: We answer can also verify answers with the help of some examples
(6X2=12) and (6X3=18), both of these are evenly divisible by 3.
Divisibility rules make it easier to identify whether some number is divisible by any or not.
As 6 = 2 X 3, all the multiples of 6 are divisible by 2 as well as 3
Complete step-by-step answer:
Divisibility rule for 6:
Since 6 = 2 X 3, all the numbers divisible by 6 are also divisible by 2 and 3
For 2: the digit at one's place should be even.
For 3: the sum of all digits should be divisible by three
Checking the options:
A) states that the multiples are all odd numbers which is wrong as the numbers divisible by 2 will always be even
B) states that all the multiples have 6 in the one’s place which can be held for the divisibility by 2 but not always in case of 3 as the sum of the rest of the numbers might not be divisible by 3.
C) states that the multiples can be evenly divided by 3 which can be held for both 2 and 3 as the numbers divisible by 2 are always even.
D) states that the multiples can be evenly divided by 12 which cannot be held true for all the multiples as 6 X 3 = 18 and is not divisible by 12
So, the correct answer is “Option C”.
Note: We answer can also verify answers with the help of some examples
(6X2=12) and (6X3=18), both of these are evenly divisible by 3.
Divisibility rules make it easier to identify whether some number is divisible by any or not.
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