Question

At any point on the perpendicular bisector of the line joining two equal and opposite charges.
A. The electric field is zero
B. The electric potential is zero
C. The electric potential decreases with increasing distance from their mid point
D. The electric field is perpendicular to the line joining the charges

Answer 1

Hint: Here we have to see whether the electric potential is a scalar or a vector quantity.
Scalar quantity gives us only the magnitude whereas a vector quantity gives us both magnitude and direction.

Complete step by step answer:
Electric force per unit charge is known as electric field. The field’s position is taken to be the position of the force on a positive test charge that will exert.
At any point in an electric field, the electrostatic potential is proportional to the amount of work per unit positive charge per unit positive test charge, or to carry the unit positive test charge from infinity to that point, against the electrostatic force without acceleration.
The difference in electrostatic potential between two points in an electric field is defined as the amount of work done in moving a positive unit test charge from one point to other point against an acceleration-free electrostatic force (i.e. the difference in electrostatic potential of the two points in the electric field.)
The distance between the two charges is equal to every point on the perpendicular bisector of the line joining the two charges. Since electrical potential is a scalar quantity and thus contributes only magnitude, due to all the charges in the perpendicular bisector, the amount of electrical potential is zero.

So, the correct answer is “Option B”.

Note:
So, in short it can be said that due to electric potential being a scalar quantity, at any point on the perpendicular bisector, the electric potential is zero.
The field’s position is taken to be the position of the force on a positive test charge that will exert.