
Assertion: Coordination number of both $N{{a}^{+}}$ and $C{{l}^{-}}$ in NaCl is 6.
Reason: Second coordination number of $C{{l}^{-}}$ in the NaCl unit is 12.
Answer
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Hint: The structure of the crystal can be calculated by seeing the radius ratio of the cations and the anions. Now, to calculate the coordination number, count the number of opposite ions present, and to calculate the second coordination number see the nearest number of the same ions in the crystal.
Complete step by step solution: NaCl is a solid crystal and we can calculate the radius ratio of the ions. The ratio of the radius of the $N{{a}^{+}}$ to the radius of $C{{l}^{-}}$ ions comes between 0.414 – 0.732, so it means that the crystal is FCC in which the chloride ions are on the face-centers and corner of the crystal and the sodium ion is over the octahedral voids.
Since the radius ratio of the NaCl is between 0.414 – 0.732, therefore, the structural arrangement is octahedral so, the coordination number of the ions is 6. This means that the number of $C{{l}^{-}}$ ions surrounding the $N{{a}^{+}}$ are 6 and vice-versa. Therefore, the assertion is correct.
Now, to calculate the second coordination number of chloride ions, we have to calculate the number of chloride ions surrounding all three axes. We know that the chloride ions are present on the face centers and corners of the crystal. When one atom is present on the corner of the crystal, then the nearest same atom will be at the center of the face as shown below:
So, one atom in the corner is attached with 4 same atoms on one axis, therefore, in all the three-axis there are 12 atoms surrounding. Hence, the second coordination number of $C{{l}^{-}}$ ion is 12.
Therefore, the assertion is correct. The reason is also correct but it is not the correct explanation for the assertion.
Note: If the radius ratio is between 0.155 – 0.225, then the first coordination number is taken 3, if the radius ratio is between 0.225 – 0.414 then the first coordination number is taken 4, and the radius ratio is between 0.732 - 1 then the first coordination number is taken 8.
Complete step by step solution: NaCl is a solid crystal and we can calculate the radius ratio of the ions. The ratio of the radius of the $N{{a}^{+}}$ to the radius of $C{{l}^{-}}$ ions comes between 0.414 – 0.732, so it means that the crystal is FCC in which the chloride ions are on the face-centers and corner of the crystal and the sodium ion is over the octahedral voids.
Since the radius ratio of the NaCl is between 0.414 – 0.732, therefore, the structural arrangement is octahedral so, the coordination number of the ions is 6. This means that the number of $C{{l}^{-}}$ ions surrounding the $N{{a}^{+}}$ are 6 and vice-versa. Therefore, the assertion is correct.
Now, to calculate the second coordination number of chloride ions, we have to calculate the number of chloride ions surrounding all three axes. We know that the chloride ions are present on the face centers and corners of the crystal. When one atom is present on the corner of the crystal, then the nearest same atom will be at the center of the face as shown below:

So, one atom in the corner is attached with 4 same atoms on one axis, therefore, in all the three-axis there are 12 atoms surrounding. Hence, the second coordination number of $C{{l}^{-}}$ ion is 12.
Therefore, the assertion is correct. The reason is also correct but it is not the correct explanation for the assertion.
Note: If the radius ratio is between 0.155 – 0.225, then the first coordination number is taken 3, if the radius ratio is between 0.225 – 0.414 then the first coordination number is taken 4, and the radius ratio is between 0.732 - 1 then the first coordination number is taken 8.
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