
Arrange in descending Order:
1, 00, 000; 99, 999; 9, 90, 000; 1, 10, 000
$
{\text{A}}{\text{. 1, 00, 000; 99, 999; 9, 90, 000, 1, 10, 000}} \\
{\text{B}}{\text{. 1, 10, 000; 9, 90, 000; 99, 999; 1,00, 000}} \\
C.{\text{ 9, 90, 000; 99, 999; 1,10, 000; 1, 00, 000 }} \\
D.{\text{ 9, 90, 000; 1, 10, 000; 1, 00, 000; 99, 999}} \\
$
Answer
623.7k+ views
Hint: Descending Order-Arranging things, i.e., numbers, quantities, lengths, etc. from a larger value to smaller value is known as descending order. It is also known as the decreasing order.
Complete step-by-step answer:
Here, numbers to be arrange in descending order are:
$1,00,000{\text{ ; 99,999 ; 9,90,000 ; 1,10,000}}$
We know that, increasing order of Indian Numbering system is${\text{Ones < Tens < Hundred < Thousands < Ten Thousands < Lakhs < Ten Lakhs < Crores}}.......$
Using the above relation we get that \[9,90,000\] is largest among all values because it is of the order of lakhs.
After \[9,90,000{\text{ }};{\text{ }}1,10,000\] is largest among values which are less than it because it is also the order of lakhs but less than 9,90,000 because 9,90,000 has 9 at lakhs place which is greater than 1.
After \[1,10,000{\text{ ; }}1,00,000\] is largest among values which are less than it because it is also of the order of lakhs but less than 1,10,000 because 1,10,000 has 1 at ten thousands pace which is greater than 0.
Finally, \[99,999\]is smallest among all values because it is of order Ten Thousands and all other values are of order greater than Ten Thousands.
Therefore, descending order of given values is:
$9,90,000{\text{ ; 1,10,000 ; 1,00,000 ; 99,999}}$
Hence, option $D.$ is correct.
Note: Whenever you get this type of question the key concept of solving is you should have knowledge about how to arrange given values in descending order (largest among all values comes first). Then repeat the same procedure of checking the largest among all remaining values until only one value is remaining.
Complete step-by-step answer:
Here, numbers to be arrange in descending order are:
$1,00,000{\text{ ; 99,999 ; 9,90,000 ; 1,10,000}}$
We know that, increasing order of Indian Numbering system is${\text{Ones < Tens < Hundred < Thousands < Ten Thousands < Lakhs < Ten Lakhs < Crores}}.......$
Using the above relation we get that \[9,90,000\] is largest among all values because it is of the order of lakhs.
After \[9,90,000{\text{ }};{\text{ }}1,10,000\] is largest among values which are less than it because it is also the order of lakhs but less than 9,90,000 because 9,90,000 has 9 at lakhs place which is greater than 1.
After \[1,10,000{\text{ ; }}1,00,000\] is largest among values which are less than it because it is also of the order of lakhs but less than 1,10,000 because 1,10,000 has 1 at ten thousands pace which is greater than 0.
Finally, \[99,999\]is smallest among all values because it is of order Ten Thousands and all other values are of order greater than Ten Thousands.
Therefore, descending order of given values is:
$9,90,000{\text{ ; 1,10,000 ; 1,00,000 ; 99,999}}$
Hence, option $D.$ is correct.
Note: Whenever you get this type of question the key concept of solving is you should have knowledge about how to arrange given values in descending order (largest among all values comes first). Then repeat the same procedure of checking the largest among all remaining values until only one value is remaining.
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