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How are xenon fluorides XeF2, XeF4 and XeF6 obtained?


Answer
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Hint: Xenon is a noble gas element having eight electrons in their outermost shell making them stable in nature. The reactions of xenon with fluorine can only be possible in some environmental conditions.

Complete step by step solution:
Let us move directly towards the formation of xenon fluorides;
Xenon fluorides- There are three binary xenon fluorides which are formed directly under appropriate experimental conditions.
The reactions for the formation of the given xenon fluorides are;
For XeF2-
Xe(g,excess)+F2(g)1bar673KXeF2(s)
Xe in excess and its gaseous state reacts with fluorine in its gaseous form at 673K temperature and 1 bar pressure to produce XeF2 solution.
XeF2 can also be formed by irradiating a mixture of xenon and fluorine with sunlight.
For XeF4-
Xe(g,1mole)+2F2(g,5moles)7bar873KXeF4(s)
Xe in its gaseous state reacts with fluorine in its gaseous form at 873K temperature and 7 bar pressure to produce XeF4 solution. The mole ratio of xenon and fluorine is 1:5 and the mixture is sealed in Ni vessels while the reaction takes place.
For XeF6-
Xe(g,1mole)+3F2(g,20moles)65bar573KXeF6(s)
Xe in its gaseous state reacts with fluorine in its gaseous form at 573K temperature and 65 bar pressure to produce XeF6 solution. The mole ratio of xenon and fluorine is 1:20 and the mixture is sealed in Ni vessels while the reaction takes place.
XeF6 can also be synthesized by interacting XeF4 with O2F2 at 143 K as,
XeF4+O2F2143KXeF6+O2

Note: Do note that synthesis of all the xenon fluorides demand for the different experimental conditions, none of the reactions are possible at similar conditions. Also, the alternatives as described above are taken into account with respective precautions and specific conditions.