
What is the approximate distance between points $\left( -7,2 \right)$ and $\left( 11,-5 \right)$?
Answer
525.6k+ views
Hint: We first use the formula of distance between two points $\left( a,b \right)$ and $\left( c,d \right)$ as $d=\sqrt{{{\left( a-c \right)}^{2}}+{{\left( b-d \right)}^{2}}}$. We then convert the root value in decimal to find the approximate value of the distance.
Complete step-by-step solution:
We have to find the distance between points $\left( -7,2 \right)$ and $\left( 11,-5 \right)$.
We first find the general formula for distance between two arbitrary points.
We take two points $\left( a,b \right)$ and $\left( c,d \right)$.
The formula for distance between those two points will be $d=\sqrt{{{\left( a-c \right)}^{2}}+{{\left( b-d \right)}^{2}}}$.
For our given points $\left( -7,2 \right)$ and $\left( 11,-5 \right)$, we put the values for $a=-7,c=11$ and $b=2,d=-5$.
Therefore, the distance between those two points is $d=\sqrt{{{\left( -7-11 \right)}^{2}}+{{\left( 2+5 \right)}^{2}}}$.
Simplifying we get $d=\sqrt{{{18}^{2}}+{{7}^{2}}}=\sqrt{373}$ units.
We now try to find the decimal value of $\sqrt{373}$.
We take 2 digits as a set from the right end and complete the division. For the decimal form we take the set from the right side of the decimal.
\[\begin{align}
& 19 \\
& 1\left| \!{\overline {\,
\begin{align}
& \overline{3}\overline{73} \\
& \underline{1} \\
\end{align} \,}} \right. \\
& 29\left| \!{\overline {\,
\begin{align}
& 273 \\
& \underline{261} \\
& 12 \\
\end{align} \,}} \right. \\
\end{align}\]
Now we have to enter the decimal part. We keep doing the breaking in the set form till 2-digit place after decimal.
\[\begin{align}
& 19.31 \\
& 383\left| \!{\overline {\,
\begin{align}
& \overline{12}.\overline{00}\overline{00}\overline{00} \\
& \underline{1149} \\
& 5100 \\
\end{align} \,}} \right. \\
& 3861\left| \!{\overline {\,
\begin{align}
& 5100\overline{00} \\
& \underline{3861} \\
& 123900 \\
\end{align} \,}} \right. \\
\end{align}\]
Note: The long-division method and arranging the set of 2 digits is different for integer and decimal. But taking double for the next division and putting a particular number is the same process for both of them. Since 373 is a non-perfect square number, we will find the value of root 373 using the long division method as shown above.
Complete step-by-step solution:
We have to find the distance between points $\left( -7,2 \right)$ and $\left( 11,-5 \right)$.
We first find the general formula for distance between two arbitrary points.
We take two points $\left( a,b \right)$ and $\left( c,d \right)$.
The formula for distance between those two points will be $d=\sqrt{{{\left( a-c \right)}^{2}}+{{\left( b-d \right)}^{2}}}$.
For our given points $\left( -7,2 \right)$ and $\left( 11,-5 \right)$, we put the values for $a=-7,c=11$ and $b=2,d=-5$.
Therefore, the distance between those two points is $d=\sqrt{{{\left( -7-11 \right)}^{2}}+{{\left( 2+5 \right)}^{2}}}$.
Simplifying we get $d=\sqrt{{{18}^{2}}+{{7}^{2}}}=\sqrt{373}$ units.
We now try to find the decimal value of $\sqrt{373}$.
We take 2 digits as a set from the right end and complete the division. For the decimal form we take the set from the right side of the decimal.
\[\begin{align}
& 19 \\
& 1\left| \!{\overline {\,
\begin{align}
& \overline{3}\overline{73} \\
& \underline{1} \\
\end{align} \,}} \right. \\
& 29\left| \!{\overline {\,
\begin{align}
& 273 \\
& \underline{261} \\
& 12 \\
\end{align} \,}} \right. \\
\end{align}\]
Now we have to enter the decimal part. We keep doing the breaking in the set form till 2-digit place after decimal.
\[\begin{align}
& 19.31 \\
& 383\left| \!{\overline {\,
\begin{align}
& \overline{12}.\overline{00}\overline{00}\overline{00} \\
& \underline{1149} \\
& 5100 \\
\end{align} \,}} \right. \\
& 3861\left| \!{\overline {\,
\begin{align}
& 5100\overline{00} \\
& \underline{3861} \\
& 123900 \\
\end{align} \,}} \right. \\
\end{align}\]
Note: The long-division method and arranging the set of 2 digits is different for integer and decimal. But taking double for the next division and putting a particular number is the same process for both of them. Since 373 is a non-perfect square number, we will find the value of root 373 using the long division method as shown above.
Recently Updated Pages
Master Class 10 Computer Science: Engaging Questions & Answers for Success

Master Class 10 General Knowledge: Engaging Questions & Answers for Success

Master Class 10 English: Engaging Questions & Answers for Success

Master Class 10 Social Science: Engaging Questions & Answers for Success

Master Class 10 Maths: Engaging Questions & Answers for Success

Master Class 10 Science: Engaging Questions & Answers for Success

Trending doubts
What is the median of the first 10 natural numbers class 10 maths CBSE

Which women's tennis player has 24 Grand Slam singles titles?

Who is the Brand Ambassador of Incredible India?

Why is there a time difference of about 5 hours between class 10 social science CBSE

Write a letter to the principal requesting him to grant class 10 english CBSE

State and prove converse of BPT Basic Proportionality class 10 maths CBSE

