Question

Antichlor is a compound that converts $\text{C}{{\text{l}}_{\text{2}}}$ into ____
A) Hydrochloric acid
B) $\text{KCl}$
C) Nitric acid
D) $\text{NaCl}$

Answer 1

Hint: An antichlor is a compound that is used to decompose the residue of hydrochloride or chlorine which are formed after the chlorine-based bleaching.it is used in the textile and paper industries for the cleaning processes. Antichlor compounds reduce the $\text{C}{{\text{l}}_{\text{2}}}$into$\text{C}{{\text{l}}^{-}}$.

Complete step by step answer:
Antichlor is a substance that is used to remove the chlorine from the material after bleaching or used to neutralize the chlorine present in the material.
An antichlor is a substance which can decompose the residual chlorine from the material after the chlorine bleaching is carried out on the material. This prevents the further reaction of chlorine with the material and protects from unwanted damage of material.
The most commonly used antichlor is sodium thiosulphates $\text{N}{{\text{a}}_{\text{2}}}{{\text{S}}_{\text{2}}}{{\text{O}}_{\text{3}}}$. It neutralizes the excess of chlorine which is left on the textile or the food pulp.
There are other examples of antichlor like sodium bisulphite $\text{NaHS}{{\text{O}}_{\text{3}}}$ , potassium bisulphite $\text{KHS}{{\text{O}}_{\text{3}}}$ , sodium metabisulphite $\text{N}{{\text{a}}_{\text{2}}}{{\text{S}}_{\text{2}}}{{\text{O}}_{\text{5}}}$ , and hydrogen peroxide ${{\text{H}}_{\text{2}}}{{\text{O}}_{\text{2}}}$.
In the textile industry, the antichlor is added to the material at the end of the bleaching process. After treating the material with the antichlor, it is rinsed thoroughly in water to remove any by-products left behind.
Let us consider that the $\text{N}{{\text{a}}_{\text{2}}}{{\text{S}}_{\text{2}}}{{\text{O}}_{\text{3}}}$ as an antichlor. Let’s see how it decomposes or removes the chlorine from the material.
$\text{ N}{{\text{a}}_{\text{2}}}{{\text{S}}_{\text{2}}}{{\text{O}}_{\text{3}}}\text{ + C}{{\text{l}}_{\text{2}}}\text{ + }{{\text{H}}_{\text{2}}}\text{O }\to \text{ S + 2HCl + N}{{\text{a}}_{\text{2}}}\text{S}{{\text{O}}_{4}}$
As we can see from the reaction above that the sodium thiosulfate reacts with the chlorine and it results in the production of sulphur, hydrogen chloride, and sodium sulfate $\text{N}{{\text{a}}_{\text{2}}}\text{S}{{\text{O}}_{4}}$.
By this process, we can remove the chlorine in the form of hydrogen chloride from the material.
It decomposes the $\text{C}{{\text{l}}_{\text{2}}}$ molecule to the hydrogen chloride $\text{HCl}$ .

Thus, (A) is the correct option.

Note: By this process, we can remove the chlorine from the paper pulp or textile. Therefore, the antichlor has nothing to do with the bleaching powder. It can only decompose the $\text{C}{{\text{l}}_{\text{2}}}$ molecules into $\text{HCl}$.