Question

What is the answer to $4\left( {7c + 2} \right) = 28c$ ?

Answer 1

Hint: We can solve this problem by usual algebraic simplification. And also we know the BODMAS rule. This simplification is based on this rule. First solve the bracket term and then multiply the bracket term by the term which is outside the bracket. Finally isolating all the terms that contain the target variable on one side of the equals and everything else on the other side and then manipulate as appropriate . Assume our target variable in this equation is $c$.

Complete step-by-step solution:
Given expression is, $4\left( {7c + 2} \right) = 28c$.
First of all we will have to expand the bracket and this is how we will get a normal solving equation and be able to find what $c$ is.
To expand the bracket using the BODMAS rule to solve the bracket. To expand the bracket we have to know that we need to multiply everything inside the bracket by the outside. Here we multiplied bracket term with $4$ we get,
$ \Rightarrow \left( {4 \times 7c + 4 \times 2} \right) = 28c$
The simplified the bracket term we get,
$ \Rightarrow 28c + 8 = 28c$ ,
Now reordering the right hand side term into the left hand side of equals, we get,
$ \Rightarrow 28c + 8 - 28c = 0$
Subtracting the term we get,
$ \Rightarrow 8 = 0$
Thus we cannot reduce anymore which leads to no solution.
This statement is clearly false and there is also no $c$ as a variable to solve for.
This indicates that there is no solution to the equation .

Note: An equation of the type $ax + b = 0$ is called a linear equation in one unknown, where $a$ and $b$ are known numbers and $x$ is an unknown value. To solve this equation means to find the numerical value of x , at which this equation becomes an identity. If the coefficients are the same on both sides then the sides will not equal, therefore no solutions will occur.