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# What is the angular displacement for the minute hand of a clock in 600 seconds?

Last updated date: 06th Sep 2024
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Hint: Angular displacement of a body is the angle in radians through which a point revolves around a centre or a line that has been rotated in a specific sense about a specified axis. So we need to find the value of the angle in degrees for the minute hand of a clock in 600 seconds.

We know that,
60 minutes is equal to 1 degree
So, 1 minute will be equal to ${{\dfrac{1}{60}}^{\circ }}$ (According to unitary method)
In other words, we can say,
60 seconds is equal to ${{\dfrac{1}{60}}^{\circ }}$
$\therefore$ 1 second is equal to ${{\dfrac{1}{60\times 60}}^{\circ }}$
Hence, in 600 seconds, the displacement of the minute hand is ${{\dfrac{360\times 600}{60\times 60}}^{\circ }}$ = 60$^{\circ }$

Thus, the total angular displacement of the minute hand of the clock is 60 degrees.

$\theta =\dfrac{l}{r}$ , where angular displacement is given by the length of the arc divided by the radius of the circle.
Fig: diagram showing the angular displacement, $\theta$