
An exothermic reaction is represented by the graph:
A.
B.
C.
D.




Answer
434.3k+ views
Hint: The relation between equilibrium constant, ${K_p}$ and Temperature is given by Van’t Hoff’s equation. The equation relates the change in the equilibrium constant of a reaction with the change in temperature and the standard enthalpy change of a reaction. And for an exothermic reaction, the standard enthalpy change is always negative. This is because energy is released during an exothermic reaction.
Complete step by step answer:
The van’t Hoff equation was proposed by a Dutch chemist Jacobus Henricus van’t Hoff in the year 1884. The van’t Hoff’s equation is given by:
$\ln {K_p} = \dfrac{{\Delta {H^0}}}{{RT}} + \dfrac{{\Delta {S^0}}}{R}$, here $\Delta {H^0}$ is the change in standard enthalpy, R is the universal gas constant, T is the temperature, ${K_p}$ is the equilibrium constant, and $\Delta {S^0}$ is the change in the entropy.
If you look at the van’t Hoff equation it is in the form $y = mx + c$ where m is the slope of the reaction and c is the intercept.
So comparing both the equations the slope of the reaction is $ - \dfrac{{\Delta {H^0}}}{R}$ , since for an exothermic change is standard enthalpy is negative, it will give us a positive slope.
So, the correct answer is Option A.
Note: The equilibrium constant of a reaction is the value of the reaction quotient of that chemical reaction at a chemical equilibrium, which is a state approached by a dynamic chemical system after sufficient time has passed at which its composition does not change further. In simple words, an equilibrium is attained when the rate of the forward reaction is equal to the rate of backward reaction.
Complete step by step answer:
The van’t Hoff equation was proposed by a Dutch chemist Jacobus Henricus van’t Hoff in the year 1884. The van’t Hoff’s equation is given by:
$\ln {K_p} = \dfrac{{\Delta {H^0}}}{{RT}} + \dfrac{{\Delta {S^0}}}{R}$, here $\Delta {H^0}$ is the change in standard enthalpy, R is the universal gas constant, T is the temperature, ${K_p}$ is the equilibrium constant, and $\Delta {S^0}$ is the change in the entropy.
If you look at the van’t Hoff equation it is in the form $y = mx + c$ where m is the slope of the reaction and c is the intercept.
So comparing both the equations the slope of the reaction is $ - \dfrac{{\Delta {H^0}}}{R}$ , since for an exothermic change is standard enthalpy is negative, it will give us a positive slope.
So, the correct answer is Option A.
Note: The equilibrium constant of a reaction is the value of the reaction quotient of that chemical reaction at a chemical equilibrium, which is a state approached by a dynamic chemical system after sufficient time has passed at which its composition does not change further. In simple words, an equilibrium is attained when the rate of the forward reaction is equal to the rate of backward reaction.
Recently Updated Pages
Master Class 9 General Knowledge: Engaging Questions & Answers for Success

Earth rotates from West to east ATrue BFalse class 6 social science CBSE

The easternmost longitude of India is A 97circ 25E class 6 social science CBSE

Write the given sentence in the passive voice Ann cant class 6 CBSE

Convert 1 foot into meters A030 meter B03048 meter-class-6-maths-CBSE

What is the LCM of 30 and 40 class 6 maths CBSE

Trending doubts
Which one is a true fish A Jellyfish B Starfish C Dogfish class 11 biology CBSE

What is the difference between superposition and e class 11 physics CBSE

State and prove Bernoullis theorem class 11 physics CBSE

1 ton equals to A 100 kg B 1000 kg C 10 kg D 10000 class 11 physics CBSE

State the laws of reflection of light

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE
