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An empty metal container (without its handle) weight 15% of its weight when filled with a particular liquid. after adding the handle, the weight of the fully filled container increases by 5%. if the weight of a partly filled container is 1/3 of the completely filled container with handle attached, then what fraction of container is utilized
(A) $\dfrac{3}{{17}}$
(B) $\dfrac{4}{{17}}$
(C) $\dfrac{6}{{19}}$
(D) $\dfrac{3}{{19}}$

Answer
VerifiedVerified
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Hint:In this question the total weight of container without handle is not given so by assuming it as 100g we can find weight of liquid and weight of container. In this we convert percentage in fraction by using \[x\% = \dfrac{x}{{100}}\] .

Complete step-by-step answer:
Now we assume that a full container without the handle weighed 100g to find the weight fraction.
So total weight of container without handle is 100g
Now according to the question the weight of an empty container is 15% of the total weight of the container.
Weight of empty container $ = \dfrac{{15 \times 100}}{{100}}$
So weight of empty container is $15g$
Now we have to find weight of liquid filled in container
Weight of liquid = total weight of container – weight of empty container
Weight of liquid =$100g - 15g$
Weight of liquid = $85g$
Now, adding a handle adds 5% or 5 grams,
So a full container with a handle would weight = $100g + 5g$
Full weight of container with handle = $105g$
 Given, the weight of a partly filled container is 1/3 of the completely filled container with handle
So weight of partly filled container = $\dfrac{1}{3} \times 105g$
Weight of partly filled container = $35g$
Now to find fraction of container utilize is find by subtracting the weights of container and the handle
 So \[35g - 5g - 15g = 15g\]
Now calculating our fraction we have,
Ratio of liquid present in partly filled container and fully filled container
 So $\dfrac{{15g}}{{85g}}$
fraction of container utilize = $\dfrac{3}{{17}}$
So option A is the correct answer.

Note:we can do this question by assuming the weight of container as variable X.
So total weight of container without handle$ = x$
Weight of container= $15\% $of $x$
$ \Rightarrow \dfrac{{15 \times x}}{{100}}$
$ \Rightarrow .15x$
Now weight of liquid filled in container
$x - .15x = .85x$
Now weight of container with handle is $x + 5\% $of $x$
$x + 0.05x$
$1.05x$
the weight of a partly filled container is 1/3 of the completely filled container with handle
So weight of partly filled container=$\dfrac{1}{3} \times 1.05x$
$ \Rightarrow .35x$
Now fraction of container utilize is find by subtracting the weights of container and the handle
$.35x - .05x - .15x$
$ \Rightarrow .15x$
Now fraction of container =$\dfrac{{.15x}}{{.85x}}$
So fraction of container = $\dfrac{3}{{17}}$