Question

When Ammoniacal common salt solution is saturated with carbon dioxide we obtain?
A.${\text{N}}{{\text{H}}_{\text{4}}}{\text{HC}}{{\text{O}}_{\text{3}}}$
B.${{\text{(N}}{{\text{H}}_{\text{4}}}{\text{)}}_2}{\text{C}}{{\text{O}}_{\text{3}}}$
C.${\text{NaHC}}{{\text{O}}_{\text{3}}}$
D.${\text{N}}{{\text{a}}_{\text{2}}}{\text{C}}{{\text{O}}_{\text{3}}}$

Answer 1

Hint: Ammonium solution of common salt is defined as the ammonia and salt with water. The representation of ammonium solution of common salt is as: $N{H_3} + NaCl + {H_2}O$. Now we have to write the reaction of this solution with carbon dioxide.

Complete step by step answer:
Let us first define the ammonium solution of common salt.
Ammonium solution of common salt is defined as the ammonia and salt with water. The representation of ammonium solution of common salt is as: $N{H_3} + NaCl + {H_2}O$. Now we have to write the reaction of this solution with carbon dioxide.
Now when this solution i.e. ammonium solution of common salt is react with or saturated with carbon dioxide then the reaction is as follows:
${\text{N}}{{\text{H}}_{\text{3}}}{\text{ + NaCl + }}{{\text{H}}_{\text{2}}}{\text{O + C}}{{\text{O}}_{\text{2}}} \to {\text{NaHC}}{{\text{O}}_{\text{3}}}{\text{ + N}}{{\text{H}}_{\text{4}}}{\text{Cl}}$.

${\text{NaHC}}{{\text{O}}_{\text{3}}}$ is formed so option C is correct.

Additional information
${\text{NaHC}}{{\text{O}}_{\text{3}}}$ is known as sodium bicarbonate or sodium hydrogen carbonate made of sodium, hydrogen, carbon and oxygen where number of sodium atoms are $1$, number of hydrogen atoms are $1$, number of carbon atoms are $1$ and number of oxygen atom are $3$.
${\text{N}}{{\text{a}}_2}{\text{C}}{{\text{O}}_{\text{3}}}$ is known as sodium carbonate made of sodium, carbon and oxygen where number of sodium atoms are $2$, number of carbon atoms are $1$ and number of oxygen atom are $3$.
${\text{N}}{{\text{H}}_{\text{4}}}{\text{HC}}{{\text{O}}_{\text{3}}}$ is known as ammonium bicarbonate made of nitrogen, hydrogen, carbon and oxygen where number of nitrogen atoms are $1$, number of hydrogen atoms are $5$, number of carbon atoms are $1$ and number of oxygen atom are $3$.
${{\text{(N}}{{\text{H}}_{\text{4}}}{\text{)}}_2}{\text{C}}{{\text{O}}_{\text{3}}}$ is known as ammonium carbonate made of nitrogen, hydrogen, carbon and oxygen where number of nitrogen atoms are $2$, number of hydrogen atoms are $8$, number of carbon atoms are $1$ and number of oxygen atom are $3$.

Note:
Oxidation number of an element: It is defined as the total number of electrons that an atom accepts or loses in order to make a chemical bond which results in the formation of a chemical compound. Here in the compound ${\text{NaHC}}{{\text{O}}_{\text{3}}}$ the oxidation number of carbon is $4$.