Question

Ammonia has a dipole moment but \[S{F_6}\] does not have.
If true enter \[1\] else enter \[0\].

Answer 1

Hint: Dipole moment is given by the distance between the two dipoles and the magnitude of charge. When a molecule has two same atoms which are at equal distance from the central atom and the bonds are in opposite directions. Then the charge will be zero and the molecule will not have a dipole moment.

Complete answer:
Ammonia is a molecule with three hydrogen atoms and one nitrogen atom. Nitrogen atom is the central atom. There are three \[N - H\] bonds and not in exactly opposite directions to each other. Thus, the ammonia molecule will have a dipole moment with pyramidal geometry.
Sulphur hexafluoride is a molecule with six fluorine atoms and one sulphur atom. The molecular formula is \[S{F_6}\].There are six \[S - F\] bonds in the molecule. The all-fluorine atoms are at equal distance from the sulphur atom. All the bonds are exactly in opposite directions to each other. Thus, the magnitude of the charge will be zero as it was cancelled.
Due to the cancellation of charges, sulphur hexafluoride does not have a dipole moment.
Thus, ammonia has a dipole moment but sulphur hexafluoride does not. It is true.

Note:
The linear molecules like carbon dioxide also do not have dipole moment as the two carbon-oxygen bonds are exactly opposite to each other and act as an opposite dipole. Thus, the molecule structure should be known while calculating the bond angle.