
Acidified water was electrolysed using an inert electrode and volume of gases liberated at STP was 168mL.The amount of electricity passed through water was
A) ${96500^0}$
B) ${9650^0}$
C) ${965^0}$
D) ${168^0}$
Answer
496.8k+ views
Hint: In this question we need to determine the amount of electricity which is passed through water. For this, students need to know and use Faraday’s law of electrolysis and use the formula to solve the questions.
Complete step-by-step answer:
Electrolysis: It is a phenomenon by which the elements are broken from their compounds and deposited at the electrodes. Cations are reduced at cathode and anions are oxidised at anion.
Faraday's First Law of Electrolysis expresses that the chemical deposition because of the progression of flow through an electrolyte is straightforwardly relative to the amount of power (coulombs) went through it.
$
m\;\alpha \;quantity\;of\;electricity,Q \\
\Rightarrow m = Z.Q \\
$
Where, Z is a constant of proportionality and is known as the electro-chemical equivalent of the substance.
Faraday’s second law of electrolysis states that, when the same quantity of electricity is passed through several electrolytes, the mass of the substances deposited are proportional to their respective chemical equivalent or equivalent weight.
$2{H_2}O \to 2{H_{2(g)}} + {O_{2(g)}}$
\[
3x = 0.168 \\
\Rightarrow x = \dfrac{{0.168}}{3} \\
\Rightarrow x = 0.056 \\
\]
Therefore,
The volume of Hydrogen is,
$
\Rightarrow {V_{{H_{2(g)}}}} = 2x \\
= 2 \times 0.056 \\
= 0.112\;L \\
$
Similarly,
The volume the oxygen is,
$
\Rightarrow {V_{{O_{2(g)}}}} = x \\
= 0.056\;L \\
$
11.2L of ${H_2}$ at STP=1F
Then, 0.112L of ${H_2}$ at STP=0.01F
Also, 0.056L of ${H_2}$ at STP=0.01F
Therefore, the amount of electricity passed = 0.01F = 965 degree Celsius
Additional Information: STP was defined as a temperature of 273.15 K (0 °C, 32 °F) and an absolute pressure of exactly 1 atmosphere (101.325 kPa).
Hence from the above solution option C is correct.
Note: When it comes to comparison, the atmospheric pressure at the top of Mount Everest is\[0.36{\text{ }}atm\]. This means that if anyone plans to boil water at the top of Mount Everest, it is more likely to boil faster at that altitude. Thus we can state that the boiling point is the temperature at which the vapour pressure of that substance equals the atmospheric pressure.
Complete step-by-step answer:
Electrolysis: It is a phenomenon by which the elements are broken from their compounds and deposited at the electrodes. Cations are reduced at cathode and anions are oxidised at anion.
Faraday's First Law of Electrolysis expresses that the chemical deposition because of the progression of flow through an electrolyte is straightforwardly relative to the amount of power (coulombs) went through it.
$
m\;\alpha \;quantity\;of\;electricity,Q \\
\Rightarrow m = Z.Q \\
$
Where, Z is a constant of proportionality and is known as the electro-chemical equivalent of the substance.
Faraday’s second law of electrolysis states that, when the same quantity of electricity is passed through several electrolytes, the mass of the substances deposited are proportional to their respective chemical equivalent or equivalent weight.
$2{H_2}O \to 2{H_{2(g)}} + {O_{2(g)}}$
$2{H_2}O$ | $2{H_{2(g)}}$ | ${O_{2(g)}}$ |
0.168 | 2x | x |
\[
3x = 0.168 \\
\Rightarrow x = \dfrac{{0.168}}{3} \\
\Rightarrow x = 0.056 \\
\]
Therefore,
The volume of Hydrogen is,
$
\Rightarrow {V_{{H_{2(g)}}}} = 2x \\
= 2 \times 0.056 \\
= 0.112\;L \\
$
Similarly,
The volume the oxygen is,
$
\Rightarrow {V_{{O_{2(g)}}}} = x \\
= 0.056\;L \\
$
11.2L of ${H_2}$ at STP=1F
Then, 0.112L of ${H_2}$ at STP=0.01F
Also, 0.056L of ${H_2}$ at STP=0.01F
Therefore, the amount of electricity passed = 0.01F = 965 degree Celsius
Additional Information: STP was defined as a temperature of 273.15 K (0 °C, 32 °F) and an absolute pressure of exactly 1 atmosphere (101.325 kPa).
Hence from the above solution option C is correct.
Note: When it comes to comparison, the atmospheric pressure at the top of Mount Everest is\[0.36{\text{ }}atm\]. This means that if anyone plans to boil water at the top of Mount Everest, it is more likely to boil faster at that altitude. Thus we can state that the boiling point is the temperature at which the vapour pressure of that substance equals the atmospheric pressure.
Recently Updated Pages
Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 Accountancy: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Master Class 11 Physics: Engaging Questions & Answers for Success

Trending doubts
1 ton equals to A 100 kg B 1000 kg C 10 kg D 10000 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

Draw a diagram of nephron and explain its structur class 11 biology CBSE

Explain zero factorial class 11 maths CBSE
