
A water jet from a fountain reaches its maximum height of $4m$ at a distance $0.5m$ from the vertical passing through the point O of the water outlet. The height of the jet above the horizontal OX at a distance of $0.75m$ from the point O is
$(a). 5m$
$(b). 6m$
$(c). 3m$
$(d). 7m$
Answer
578.4k+ views
Hint:
We need to figure out what is given. Here we get the parabola and we can also have the value of height and distance once we mark the point in a diagram we can easily get the height of the jet when the distance is $0.75m$ by using roots of the parabola.
Complete step by step solution:
A water jet from a fountain reaches its maximum height of $4m$ at a distance $0.5m$ from the vertical passing through the point O of the water outlet. So the jet starts at the initial point $0$ which means $(0,0)$ and reaches the maximum height of $4m$ a distance $0.5m$ which means $(0.5,4)$ and the end point $(0,1)$ We need to find the height at a distance of $0.75m$ which means $(0.75,h)$.
This represents the parabola, now we need to find the height of the jet above the horizontal OX at a distance of $0.75m$ from the point O
This is the parabola so the roots of the parabola are
$\Rightarrow y=a(x-r)(x-s)$
We take the point $(0,1)$ as $r=0,s=1$
Apply this to the roots of the parabola,
$\Rightarrow y=a(x-0)(x-1)$
$\Rightarrow y=ax(x-1)\to (1)$
Now we take the maximum height of $4m$at a distance of $0.5m$ so the $x$ coordinate is $0.5m$ and $y$coordinate is $4m$. Apply this to equation $(1)$
$\Rightarrow 4=a(0.5)(0.5-1)$
Multiply this we get,
$\Rightarrow 4=a(0.5)(-0.5)$
$\Rightarrow a=-\dfrac{4}{(0.5)(0.5)}$
Multiply and divide by $100$ to take the decimal out
$\Rightarrow a=-\dfrac{400}{25}$
$\Rightarrow a=-16$
Now apply this to equation $(1)$we get,
$\Rightarrow y=-16(x)(x-1)\to (2)$
Now using this we can the height of the jet above the horizontal OX at a distance of $0.75m$, thus the $x$ coordinate is $0.75m$ and $y$coordinate is $h$
Apply this to equation $(2)$
$\Rightarrow h=-16(0.75)(0.75-1)$
$\Rightarrow h=-16(0.75)(-0.25)$
Multiply this we get,
$\Rightarrow h=3m$
The height of the jet above the horizontal OX at a distance of $0.75m$ from the point O is $3m$.
Note:
One more example for parabola, when liquid is rotated the forces of gravity result in the liquid forming a parabola-like shape. Definition of parabola is, it’s a locus of such a point which has an equal distance from a fixed line and a fixed point. The value of eccentricity for parabola is one.
We need to figure out what is given. Here we get the parabola and we can also have the value of height and distance once we mark the point in a diagram we can easily get the height of the jet when the distance is $0.75m$ by using roots of the parabola.
Complete step by step solution:
A water jet from a fountain reaches its maximum height of $4m$ at a distance $0.5m$ from the vertical passing through the point O of the water outlet. So the jet starts at the initial point $0$ which means $(0,0)$ and reaches the maximum height of $4m$ a distance $0.5m$ which means $(0.5,4)$ and the end point $(0,1)$ We need to find the height at a distance of $0.75m$ which means $(0.75,h)$.
This represents the parabola, now we need to find the height of the jet above the horizontal OX at a distance of $0.75m$ from the point O
This is the parabola so the roots of the parabola are
$\Rightarrow y=a(x-r)(x-s)$
We take the point $(0,1)$ as $r=0,s=1$
Apply this to the roots of the parabola,
$\Rightarrow y=a(x-0)(x-1)$
$\Rightarrow y=ax(x-1)\to (1)$
Now we take the maximum height of $4m$at a distance of $0.5m$ so the $x$ coordinate is $0.5m$ and $y$coordinate is $4m$. Apply this to equation $(1)$
$\Rightarrow 4=a(0.5)(0.5-1)$
Multiply this we get,
$\Rightarrow 4=a(0.5)(-0.5)$
$\Rightarrow a=-\dfrac{4}{(0.5)(0.5)}$
Multiply and divide by $100$ to take the decimal out
$\Rightarrow a=-\dfrac{400}{25}$
$\Rightarrow a=-16$
Now apply this to equation $(1)$we get,
$\Rightarrow y=-16(x)(x-1)\to (2)$
Now using this we can the height of the jet above the horizontal OX at a distance of $0.75m$, thus the $x$ coordinate is $0.75m$ and $y$coordinate is $h$
Apply this to equation $(2)$
$\Rightarrow h=-16(0.75)(0.75-1)$
$\Rightarrow h=-16(0.75)(-0.25)$
Multiply this we get,
$\Rightarrow h=3m$
The height of the jet above the horizontal OX at a distance of $0.75m$ from the point O is $3m$.
Note:
One more example for parabola, when liquid is rotated the forces of gravity result in the liquid forming a parabola-like shape. Definition of parabola is, it’s a locus of such a point which has an equal distance from a fixed line and a fixed point. The value of eccentricity for parabola is one.
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