Question

A transition Element has configuration , in its Oxidation State. Its atomic number is
A. $25$
B. $26$
C. $22$
D. $19$

Answer 1

Hint:Oxidation state is the state of an element after bond formation with other. elements where it has either gained or lost the electron. The oxidation state of the element depends on numbers of electrons gained or lost by element. If Electrons are gained by an element then it will have a negative Oxidation State and if it will lose electrons then it will have a positive Oxidation State.

Complete step-by-step answer:here we can see that the electronic configuration of this element $X$ is given as $\left[ {Ar} \right]$$3{d^4}$.Here $Ar$ means organ and atomic number of argon is $18$.
And after $Ar$ $3{d^4}$ and $ + 3$ Oxidation State and plus oxidation number means it had donated its electron
If we assume a basic element to be in ground state then the electronic configuration will be this $\left[ {Ar} \right]3{d^5}4{S^2}$.
And this is the electronic configuration of Manganese. And Manganese has an atomic number $25$.
Another way we can see this x element has $25$ electrons in its ground state which means it will also have $25$ protons. The number of protons determine the atomic number of an element therefore the atomic number will be $25$.

Hence Option A is correct.

Note:The transition elements have low ionization energies therefore They can have a wide range of oxidation states or positively charged forms. The positive oxidation states allow transition elements to form many different ionic and partially ionic compounds.