Question

A student scores 40 marks in an examination and fails by 26 marks. If the passing percentage is 33 then find the maximum marks in the examination.

Answer 1

Hint: In this question the given is a student scores 40 marks in an examination and fails by 26 marks. We have to find the maximum marks in the examination. and it is given that the passing percentage is 33. By using the above data we have to solve the problem. First we are going to find the pass marks using the passing percentage. Then we find the maximum marks in the examination.

Complete step by step solution:
It is given in the question that a student scores 40 marks in an examination and fails by 26 marks.
And it is also given that the pass percentage is 33.
With the help of the given information we have to find the maximum marks of the examination.
From given we can say that the addition of the student score with the required mark to pass we get total mark to get pass that is
Score required to pass the examination \[ = 40 + 26 = 66\] marks
 Also given that the pass mark is 33 percentage of total mark, with the help of the percentage formula we get,
$\Rightarrow$\[33\% = \dfrac{{33}}{{100}}\]
We know that total maximum mark multiplied with 33 percentage is 66 marks therefore we get,
$\Rightarrow$\[{\rm{total marks }} \times 33\% = 66\]
By applying the percentage value we get,
$\Rightarrow$\[{\rm{total marks }} \times \dfrac{{33}}{{100}} = 66\]
On solving we get,
$\Rightarrow$\[{\rm{total marks }} = 66 \times \dfrac{{100}}{{33}}\]
Let us cancel the terms and multiply the remaining we get
$\Rightarrow$\[{\rm{total marks = 200}}\]

$\therefore$ The maximum marks in the given examination is 200 marks

Note: In this problem we just used a concept of percentage calculation and value find for the percentage. Like this problem we have to think and understand simple logic that what we have and what we have to find. This will give us the required solution.
A candidate scores \[x\% \] is an examination fails by ‘a’ marks, while another candidate who scores \[y\% \] marks and get b marks more than the maximum required passing marks, then the maximum marks for the examination is given by
\[M = \dfrac{{100 \times \left( {a + b} \right)}}{{y - x}}\]