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A square and a regular hexagon have equal perimeters. Then their areas are in the ratio:

Answer
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Hint: Here from the given perimeters we will find the side of square and hexagon. And with the help of it we will find the ratio of their areas.

Formula used:
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Let, the side of a square is a
The perimeter of a square is = 4a
The area of a square is a2
Let, the side of a regular hexagon is b
The perimeter of the regular hexagon is = 6b
The area of a square is 332b2

Complete step-by-step answer:
It is given that the square and a regular hexagon have equal perimeters.
If the side of a square is a
The perimeter of the square is = 4a
And if the side of the regular hexagon is b,
The perimeter of the regular hexagon is = 6b
Then by the given condition, we have
4a=6b
Let us solve the above equation to find “a”, we get,
a=6b4=3b2…..(1)
Let us mark it as equation (1)
The area of the square is a2when the side of the square is a.
The area of the regular hexagon is 332b2when the side of the regular hexagon is b.
Then the ratio of the area of the square and the regular hexagon is found by dividing both the areas,
a2332b2
Let us substitute equation (1) in the above equation we get,
=(3b2)2332b2
Let us now solve the above equation we get,
=9b24×233b2
We have found that,
a2332b2=32

Hence the ratio of the area of the square and the regular hexagon is 3:2 .

Note:Square:
In geometry, a square is a regular quadrilateral that has four equal sides and four equal angles.
Hexagon:
A hexagon is a six-sided polygon or 6-gon.The total of the internal angles of a hexagon is 720°.
Ratio is found by dividing the values for which we have to find the ratio.