
A spectrometer gives the following reading when used to measure the angle of a prism main scale reading: \[58\cdot 5\text{ degree}\], vernier scale reading: 9 divisions. Given that 1 division of the main scale corresponds to \[0\cdot 5\] degree. Total Divisions on the vernier scale is 30 and match with 29 divisions of the main scale. The angle of the prism from above data?
A. \[58\cdot 59\text{ degree}\]
B. \[58\cdot 77\text{ degree}\]
C. \[58\cdot 65\text{ degree}\]
D. 59 degree
Answer
594.6k+ views
Hint: Spectrometer is an optical instrument used to study the spectra of different sources of light and to measure the refractive indices of materials. It consists of basically three parts: collimator, prism table and telescope. Here it is used to measure the angle of a prism.
Complete step by step answer:
GIVEN
Main scale Reading (MSR) \[=58\cdot 5\text{ degree}\]
Vernier scale Reading (VSR) = 9 Divisions
1 Division of main scale (1MSD) \[=0\cdot 5{}^\circ \]
Also 30 vernier scale divisions are equal to 29 main scale divisions.
So, \[30\text{ VSD}=29\text{ MSD}\]
\[\Rightarrow \text{1 VSD}=\dfrac{29}{30}\text{ MSD}\]
Least count of vernier: It is the smallest value that can be measured by any instrument.
L.C. of vernier \[=1\text{MSD}-1\text{VSD}\]
\[=\text{0}\cdot \text{5}{}^\circ -\dfrac{29}{30}\times 0\cdot 5{}^\circ \]
\[=\dfrac{0\cdot 5{}^\circ }{30}\]
\[\text{Reading of vernier = main scale reading + (vernier scale reading } \times \text{ Least count)}\]
Reading of vernier \[\text{=58}\cdot \text{5}{}^\circ \text{+}\left( 9\times \dfrac{0\cdot 5{}^\circ }{30} \right)\]
\[=58\cdot 65{}^\circ \]
So, the correct answer is “Option C”.
Note:
At the time of calculating the least count of vernier it is needed to multiply the value of 1 main scale division to vernier scale division.
Complete step by step answer:
GIVEN
Main scale Reading (MSR) \[=58\cdot 5\text{ degree}\]
Vernier scale Reading (VSR) = 9 Divisions
1 Division of main scale (1MSD) \[=0\cdot 5{}^\circ \]
Also 30 vernier scale divisions are equal to 29 main scale divisions.
So, \[30\text{ VSD}=29\text{ MSD}\]
\[\Rightarrow \text{1 VSD}=\dfrac{29}{30}\text{ MSD}\]
Least count of vernier: It is the smallest value that can be measured by any instrument.
L.C. of vernier \[=1\text{MSD}-1\text{VSD}\]
\[=\text{0}\cdot \text{5}{}^\circ -\dfrac{29}{30}\times 0\cdot 5{}^\circ \]
\[=\dfrac{0\cdot 5{}^\circ }{30}\]
\[\text{Reading of vernier = main scale reading + (vernier scale reading } \times \text{ Least count)}\]
Reading of vernier \[\text{=58}\cdot \text{5}{}^\circ \text{+}\left( 9\times \dfrac{0\cdot 5{}^\circ }{30} \right)\]
\[=58\cdot 65{}^\circ \]
So, the correct answer is “Option C”.
Note:
At the time of calculating the least count of vernier it is needed to multiply the value of 1 main scale division to vernier scale division.
Recently Updated Pages
Master Class 12 Economics: Engaging Questions & Answers for Success

Master Class 12 Physics: Engaging Questions & Answers for Success

Master Class 12 English: Engaging Questions & Answers for Success

Master Class 12 Social Science: Engaging Questions & Answers for Success

Master Class 12 Maths: Engaging Questions & Answers for Success

Master Class 12 Business Studies: Engaging Questions & Answers for Success

Trending doubts
Which are the Top 10 Largest Countries of the World?

What are the major means of transport Explain each class 12 social science CBSE

Draw a labelled sketch of the human eye class 12 physics CBSE

Why cannot DNA pass through cell membranes class 12 biology CBSE

Differentiate between insitu conservation and exsitu class 12 biology CBSE

Draw a neat and well labeled diagram of TS of ovary class 12 biology CBSE

