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A red colored mixed oxide (X) on treatment with concentrate $HN{{O}_{3}}$ gives a compound (Y). (Y) with $HCl$, produces a chloride compound (Z) which can also be produced by treating (X) with concentrated $HCl$. Compounds (X), (Y) and (Z) will be:
A. $M{{n}_{3}}{{O}_{4}},Mn{{O}_{2}},MnC{{l}_{2}}$
B. $P{{b}_{3}}{{O}_{4}},Pb{{O}_{2}},PbC{{l}_{2}}$
C. $F{{e}_{3}}{{O}_{4}},F{{e}_{2}}{{O}_{3}},FeC{{l}_{2}}$
D. $F{{e}_{3}}{{O}_{4}},F{{e}_{2}}{{O}_{3}},FeC{{l}_{3}}$

Answer
VerifiedVerified
469.2k+ views
Hint: An oxide is a chemical compound which contains at least one oxygen atom and one other element. Oxide itself is defined as the dianion of oxygen atom which is represented by the formula ${{O}^{2-}}$ and due to this it is said metal oxide contains an anion of oxygen in -2 oxidation state.

Complete Solution :
 In the given question it is said that a red colored mixed oxide (X) on treatment with concentrate $HN{{O}_{3}}$ gives a compound (Y). (Y) with $HCl$, produces a chloride compound (Z) which can also be produced by treating (X) with concentrated $HCl$. Compounds (X), (Y) and (Z) will be $P{{b}_{3}}{{O}_{4}},Pb{{O}_{2}},PbC{{l}_{2}}$ which can be discussed on the following reactions:
$P{{b}_{3}}{{O}_{4}}$ is a red colored oxide when it reacts with $HN{{O}_{3}}$ it produces $Pb{{O}_{2}}$, lead nitrate and water which can be shown as, while $Pb{{O}_{2}}$ is the major product.
$P{{b}_{3}}{{O}_{4}}+HN{{O}_{3}}\to 2Pb{{(N{{O}_{3}})}_{2}}+Pb{{O}_{2}}+2{{H}_{2}}O$
And then $Pb{{O}_{2}}$ reacts with $HCl$ and form $PbC{{l}_{2}}$ along with water and chlorine gas
which can be represented by the following reaction:
$Pb{{O}_{2}}+4HCl\to C{{l}_{2}}+2{{H}_{2}}O+PbC{{l}_{2}}$
And $PbC{{l}_{2}}$ can also be produced by treating $P{{b}_{3}}{{O}_{4}}$ directly with $HCl$.
So, the correct answer is “Option B”.

Note: Oxides have many industrial or chemical applications. Lead oxide is used in the manufacturing of glass but it also has some adverse effect on human health as it can cause irritation to skin, eyes and respiratory tract.