Question

A radio operator broadcast on the \[6\] -Meter Band the Frequency of this electromagnetic radiation is ____ $Mhz$

Answer 1

Hint:The $6$ -meter band is the smallest part of the very high frequency $(VHF)$ radio spectrum available to amateur radio operators. The term refers to a signal wavelength of $6$ metres on average.

Complete step by step answer:
The fundamental physical constant $c$, or the speed of light in a vacuum, is significant in many areas of physics. The relation between wavelength and frequency is that the speed of light is the product of the frequency and the wavelength.
We can represent the above statement like this: $c = \lambda v$
Where $c$ represents the speed of light, $\lambda $ represents the wavelength in metre and $v$ represents the frequency in ${s^{ - 1}}$ or Hertz.
$c = \lambda v$
we have to find the frequency of the electromagnetic radiation, so we rearrange the equation, and we get,
$v = \dfrac{c}{\lambda } \to (i)$
We already know that the speed of light is equal to $3.00 \times {10^8}m.{\sec ^{ - 1}}$ , and from the question, we know that the wavelength is equal to $6m$.Now we substitute the values of speed of light and wavelength in equation $(i)$ and we get,
$v = \dfrac{{\left( {3.0 \times {{10}^8}} \right)}}{6} \\
\Rightarrow v= 50 \times {10^6}Hz$
we know that $1\,MHz = {10^6}\,Hz$ , and so we get $v = 50\,MHz$

Therefore, a radio operator broadcast on the $6$ -Meter Band the Frequency of this electromagnetic radiation is $50\,MHz$.

Additional Information: The highest energy, shortest wavelengths, and highest frequencies are found in gamma rays. Radio waves, on the other side, have the smallest energies, longest wavelengths, and lowest frequencies of any kind of Electromagnetic Radiation.

Note: The electromagnetic spectrum encompasses electromagnetic waves with frequencies varying from below one hertz to above ${10^{25}}$ hertz, equivalent to wavelengths ranging from thousands of kilometres to a fraction of an atomic nucleus's size.