Question

A plant of F1 generation with genotype "AABbCC", on selfing of this plant, what is the phenotypic ratio in F2 generation?
A. 3:1
B. 1:1
C. 9:3:3:1
D. 27:9:9:9:3:3:3:1

Answer 1

Hint: George Mendel was the German scientist who discovered so many thing regarding genetics and he is considered as the founder of modern genetics, where he is the one who proposed various type of experiments and proposed three laws such as law of independent assortment, law of inheritance, and law of segregation.

Complete answer: The term F1 generation means first Filial generation where the two distinct genes cross each other in this type, where in this cross desired goals are not obtained, as in this type of cross some traits do not show up.
If in F1 generation there are some dominant genes present and as well as recessive genes that are crossed but, the appearance of dominant genes can only be seen.
In F2 generation, the crossing done by selfing of the F1 generation where both traits that are used in F1 generation appeared in the phenotype of the F2 generation and along with them some new and variant traits also appeared.
In the above given question the genotype of F1 generation is AABbCC where the calculation of number of gametes that are obtained by crossing can be obtained by formula $2^n$ where n represents the number of heterozygous gametes.
In the given genotype, the number of heterozygous gametes are $2^1$ which means 2.
Which means there is a formation of 2 gametes that are ABC and AbC.
On the selfing of the plants of F1 generation the phenotypes that are formed in F2 generation are in the ratio of 3:1.
So, the correct answer is “Option A”.

Note: In genetics, during crossing experiments of different traits, generally P represents the parental generation, and if the traits of P are crossed then the offspring obtained are considered as filial generation that is F1 and the selfing of F1 produces the F2 generation.