Question

# A piece of wire is $\dfrac{7}{8}\,m$ long and is broken into two pieces. One piece was $\dfrac{1}{4}\,m$ long. How long is the other piece?

It is written in the question that the total length of the piece of wire is $\dfrac{7}{8}\,m$
Further it is broken into two pieces. The length of one piece is given as $\dfrac{1}{4}\,m$
$\dfrac{1}{4}\,m$+ Length of second piece =$\dfrac{7}{8}\,m$
Length of second piece$= \dfrac{7}{8} - \dfrac{1}{4} = \dfrac{{7 - 2}}{8} = \dfrac{5}{8}$
So Length of second piece is $\dfrac{5}{8}$ meters
Suppose the length of wire was $=$$\dfrac{7}{8}\,m$ and it got broken into two equal pieces. So now the length of one of both the pieces can be obtained by dividing original length by $2$
So the length of each piece $= \dfrac{7}{{8 \times 2}} = \dfrac{7}{{16}}$ meters.