Question

A pale blue liquid which obtained by equi molar mixture of two gases at -$30{}^\circ C$is:
A. ${{N}_{2}}O$
B. ${{N}_{2}}{{O}_{3}}$
C. ${{N}_{2}}{{O}_{4}}$
D. ${{N}_{2}}{{O}_{5}}$

Answer 1

Hint: Equimolar solutions are generally those solutions which contain an equal number of moles and it can also be defined as those substances which equal molar concentrations. It may be solid or in powdered form but generally it is present as liquid.

Complete step by step answer: Mole is generally represented as mol and it can be defined as the unit of measurement for the amount of substance in SI units where SI represents International System of Units. A mole of any substance or particle can be defined as $6.02214076\times {{10}^{23}}$ particles which can be atoms, molecules or ions.
${{N}_{2}}{{O}_{3}}$ is a pale blue liquid which obtained by equi molar mixture of two gases at $30{}^\circ C$is and it can be explained by the following reaction
$N{{H}_{4}}N{{O}_{3}}\to N{{O}_{2}}+2{{H}_{2}}O$
In this case $N{{O}_{2}}$ is exist as:
$N\equiv N\to O$, $N$ is $sp$ hybridized having linear structure and exists as a polar molecule.
Another reaction which exert second gas can be considered as
$3Cu+8HN{{O}_{3}}\to 3Cu{{(N{{O}_{3}})}_{2}}+2NO$
Two gases involved during these reaction are $N{{O}_{2}}$ and $NO$ when mixed in equimolar concentration then it forms a pale blue liquid at temperature -$30{}^\circ C$ and reaction can be shown as follows:
$NO+N{{O}_{2}}\rightleftarrows {{N}_{2}}{{O}_{3}}$

Hence, from this we can say that option B is the correct answer.

Note: ${{N}_{2}}{{O}_{3}}$ is the chemical compound known by the name dinitrogen trioxide which is only isolable at low temperatures i.e. exist in liquid and solid phase and at higher temperature it favors the constituent gases.