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A number that has 0, 2, 4, 6 or 8 in its ones place is divisible by ________
A. 0
B. 2
C. 4
D. 6

Answer
VerifiedVerified
570.6k+ views
Hint: In order to check the divisibility of numbers, here we have to follow the divisibility rules
for each of the given numbers 0, 2, 4 and 6 separately to find the answer to the question.
We cannot divide any number by zero because the result will become undefined.
Thus, option A is incorrect.
We know that all the even numbers are divisible by 2. Thus, when the last digit of a number ends
with 0, 2, 4, 6 or 8 then that number is divisible by 2.
Thus, option B is correct.
A number is divisible by 4 when the last two digits of the number can be divided by 4. In this
case tenth place is not given so we cannot say surely that the number that has 0, 2, 4, 6 or 8 in its
one’s place is divisible by 4.
Thus, option C is incorrect.
Similarly, a number is divisible by 6 if only the number is divisible by both 3 and 2. From the
given data we see that any number ends with 0, 2, 4, 6 or 8 is divisible by 2 but it may not be
divisible by 3.
Thus, option D is incorrect.
Note: In this problem, we have to determine the divisibility of a number that has 0, 2, 4, 6 or 8 in
it's one’s place. Since the divisor are given, so by checking the condition for divisibility of each
divisor we get our required answer.