Question

A man takes $ 6 $ hours $ 30 $ min in going by a cycle and coming back scooter. He would have lost $ 2 $ hours $ 10 $ min by going on cycle both ways. How long it will take him to go by scooter both ways:
A. $ 2\;hrs $
B. $ 4\dfrac{1}{3}\;hrs $
C. $ 3\dfrac{1}{3}\;hrs $
D. $ 5\dfrac{1}{3}\;hrs $

Answer 1

Hint: Take out the time lost by the person on one side by going by scooter on one side. So, that it gives the time taken by the person going on cycle both ways. Time loss on both ways will be double of time loss one one way.

Complete step-by-step answer:
As per given in the question the person loses $ 2 $ hours $ 10 $ min in going by a cycle and coming back by scooter.
If the person will go by scooter and come back by scooter man will lose $ 2 $ hours $ 10 $ min again.
So, the time taken by the man to go by scooter both ways is:
 $ 6\;hrs\;30\;\min - 2\;hrs\;10\;\min = 4\;hrs\;20\;\min $
Now convert the time taken by the person to go by scooter both the ways in hours to get the option.
As we know that there is always $ 60\;\min $ for each hour. So, $ 20\;\min $ is equal to $ \dfrac{1}{3}\;hrs $ .
So, the time taken by the person is $ 4\;hrs\;20\;\min = 4\dfrac{1}{3}\;hrs $ .
So, the correct answer is “Option B”.

Note: Remember that the time given in the question is of the person going by cycle and coming back by the scooter not the time taken for going by cycle both ways. Subtract the time accordingly from the given time for the required time in hours.