
A man of 60 kg carries a stone of 20 kg to a height of 30m. Calculate the work done by the man.
Answer
586.2k+ views
Hint: This type of question is easy to answer as they are directly derived from the formula. We just need to apply them and substitute the value. Work done is asked and a man is carrying a stone to a height of 30m which gives clear vision of using potential energy which is $W = mgh$ where, m is the mass, g is the gravity, and h is the height.
Complete step by step answer:
Step 1:
Before proceeding to the question let us see some important definition for the solution purpose:
Definition of work done: Work, in physics, measure of energy transfer that occurs when an object is moved over a distance by an external force at least part of which is applied in the direction of the displacement. If the force is being exerted at an angle$\theta $ to the displacement, the work done is W=$fd\cos \theta $
To show that work done (kinetic energy) is equal to the increase in potential energy, turn the scenario around: Work gained (increase in KE) is equal to decrease in PE, as a weight of mass m drops a height of h.
If an object's kinetic energy doesn't change, then no work is done. Another Equation for Calculating Work: Work = Mass × Gravity × Height or MGH and is measured in Joules.
Step 2:
We are given that: mass of a man is ${m_m} = 60Kg$
Mass of the stone is ${m_s} = 20Kg$
Height equal to 30m
We need to calculate the work done by the man.
Now the work done is $W = mgh$ where, m is the mass, g is the gravity, and h is the height.
Here m =${m_m} + {m_s}$
Substituting the value in work done we get W=$\left( {{m_m} + {m_s}} \right) \times g \times h$
$ \Rightarrow W = \left( {60 + 20} \right)10 \times 30$ , which on solving gives work done equal to 24000 J
Hence the work done is 24000 J
Note: The formula of work done is expressed in joules and can find with the help of kinetic or potential energy. Here we have used potential energy because of two reasons. First is there is no velocity mentioned which is necessary in kinetic and also here mention that a man is lifting a stone which gives us a clear option to choose potential energy.
Complete step by step answer:
Step 1:
Before proceeding to the question let us see some important definition for the solution purpose:
Definition of work done: Work, in physics, measure of energy transfer that occurs when an object is moved over a distance by an external force at least part of which is applied in the direction of the displacement. If the force is being exerted at an angle$\theta $ to the displacement, the work done is W=$fd\cos \theta $
To show that work done (kinetic energy) is equal to the increase in potential energy, turn the scenario around: Work gained (increase in KE) is equal to decrease in PE, as a weight of mass m drops a height of h.
If an object's kinetic energy doesn't change, then no work is done. Another Equation for Calculating Work: Work = Mass × Gravity × Height or MGH and is measured in Joules.
Step 2:
We are given that: mass of a man is ${m_m} = 60Kg$
Mass of the stone is ${m_s} = 20Kg$
Height equal to 30m
We need to calculate the work done by the man.
Now the work done is $W = mgh$ where, m is the mass, g is the gravity, and h is the height.
Here m =${m_m} + {m_s}$
Substituting the value in work done we get W=$\left( {{m_m} + {m_s}} \right) \times g \times h$
$ \Rightarrow W = \left( {60 + 20} \right)10 \times 30$ , which on solving gives work done equal to 24000 J
Hence the work done is 24000 J
Note: The formula of work done is expressed in joules and can find with the help of kinetic or potential energy. Here we have used potential energy because of two reasons. First is there is no velocity mentioned which is necessary in kinetic and also here mention that a man is lifting a stone which gives us a clear option to choose potential energy.
Recently Updated Pages
Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 Business Studies: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Trending doubts
There are 720 permutations of the digits 1 2 3 4 5 class 11 maths CBSE

Discuss the various forms of bacteria class 11 biology CBSE

Draw a diagram of a plant cell and label at least eight class 11 biology CBSE

Explain zero factorial class 11 maths CBSE

What organs are located on the left side of your body class 11 biology CBSE

Draw a diagram of nephron and explain its structur class 11 biology CBSE

