
A man is running towards a plane mirror at a speed of $2m{s^{ - 1}}$. How fast does he see himself running towards his image?
A.2m/s
B.4m/s
C.5m/s
D.3m/s
Answer
529.8k+ views
Hint: Here in this question we have to keep in mind that the person who is standing in front of the mirror seeing his image is approaching his image at $2m{s^{ - 1}}$. As he is approaching his image, the image is also approaching him at the same speed, so the two speeds will be added.
Complete answer:
Here the person will cover the given amount of distance in the required amount of time at the rate of $2m{s^{ - 1}}$. In reality the person would have the same speed of $2m{s^{ - 1}}$ but he would see himself running towards his image at $4m{s^{ - 1}}$. This is so because the image is also running towards him at the speed of $2m{s^{ - 1}}$ so, both of the velocities would add up ($2m{s^{ - 1}}$ of the person running towards his image +$2m{s^{ - 1}}$ of the image running towards the person =$4m{s^{ - 1}}$). It is an illusion that the person sees himself running towards his image. In actuality the person is running at his original speed of $2m{s^{ - 1}}$. The man is running towards a plane mirror at a speed of $2m{s^{ - 1}}$. Sees himself running towards his image at the speed of $4m{s^{ - 1}}$.
So, Option (B) is the correct answer:
Note:
Here, one can be easily mistaken and give the answer $2m{s^{ - 1}}$ which is the person’s real speed/velocity. One has to read the question carefully to know that in the question it is asked the total speed at which the person sees himself running towards his image.
Complete answer:
Here the person will cover the given amount of distance in the required amount of time at the rate of $2m{s^{ - 1}}$. In reality the person would have the same speed of $2m{s^{ - 1}}$ but he would see himself running towards his image at $4m{s^{ - 1}}$. This is so because the image is also running towards him at the speed of $2m{s^{ - 1}}$ so, both of the velocities would add up ($2m{s^{ - 1}}$ of the person running towards his image +$2m{s^{ - 1}}$ of the image running towards the person =$4m{s^{ - 1}}$). It is an illusion that the person sees himself running towards his image. In actuality the person is running at his original speed of $2m{s^{ - 1}}$. The man is running towards a plane mirror at a speed of $2m{s^{ - 1}}$. Sees himself running towards his image at the speed of $4m{s^{ - 1}}$.
So, Option (B) is the correct answer:
Note:
Here, one can be easily mistaken and give the answer $2m{s^{ - 1}}$ which is the person’s real speed/velocity. One has to read the question carefully to know that in the question it is asked the total speed at which the person sees himself running towards his image.
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