
A magnetic field exerts no force on:
A. A magnet
B. An unmagnetized iron bar
C. A moving charge
D. Stationary charges
Answer
566.1k+ views
Hint: In this question, we need to comment where a magnetic field exerts no force. For this, we will use the definition of the magnetic field and follow the properties of the magnetic fields as well.
Complete step by step answer:
Lorentz equation for magnetic force is given as \[F = q\left( {V \times B} \right)\], where \[q\] is the amount of electric charge, \[V\] is the velocity of charge, \[B\] is magnetic flux and \[F\] is the Magnetic force.
We know that the magnetic force on a charged particle is given as
\[F = q\left( {V \times B} \right)\] where velocity of the charge is perpendicular to the magnetic field. When we pace a stationary charge in the magnetic field it experiences no force on it since the velocity of the particle is zero.
We know magnetic force on a charged particle is given as
\[F = q\left( {V \times B} \right) - - (i)\]
Since the stationary charges has no velocity to it so \[V = 0\],
Now by substituting the velocity \[V = 0\] in equation (i), we get
$
F = q\left( {0 \times B} \right) \\
\therefore F= 0 \\
$
Hence we can say when stationary charges are placed in the magnetic field they experience no force on them.
So, the correct answer is “Option D”.
Note:
Students must note that the work done in moving a charged particle between two points is equal to zero in the magnetic field because the magnetic force is always perpendicular to the velocity of that charged particle.
Complete step by step answer:
Lorentz equation for magnetic force is given as \[F = q\left( {V \times B} \right)\], where \[q\] is the amount of electric charge, \[V\] is the velocity of charge, \[B\] is magnetic flux and \[F\] is the Magnetic force.
We know that the magnetic force on a charged particle is given as
\[F = q\left( {V \times B} \right)\] where velocity of the charge is perpendicular to the magnetic field. When we pace a stationary charge in the magnetic field it experiences no force on it since the velocity of the particle is zero.
We know magnetic force on a charged particle is given as
\[F = q\left( {V \times B} \right) - - (i)\]
Since the stationary charges has no velocity to it so \[V = 0\],
Now by substituting the velocity \[V = 0\] in equation (i), we get
$
F = q\left( {0 \times B} \right) \\
\therefore F= 0 \\
$
Hence we can say when stationary charges are placed in the magnetic field they experience no force on them.
So, the correct answer is “Option D”.
Note:
Students must note that the work done in moving a charged particle between two points is equal to zero in the magnetic field because the magnetic force is always perpendicular to the velocity of that charged particle.
Recently Updated Pages
Master Class 12 English: Engaging Questions & Answers for Success

Master Class 12 Economics: Engaging Questions & Answers for Success

Master Class 12 Social Science: Engaging Questions & Answers for Success

Master Class 12 Maths: Engaging Questions & Answers for Success

Master Class 12 Chemistry: Engaging Questions & Answers for Success

Master Class 12 Business Studies: Engaging Questions & Answers for Success

Trending doubts
What are the major means of transport Explain each class 12 social science CBSE

Which are the Top 10 Largest Countries of the World?

Draw a labelled sketch of the human eye class 12 physics CBSE

Explain sex determination in humans with line diag class 12 biology CBSE

The pH of the pancreatic juice is A 64 B 86 C 120 D class 12 biology CBSE

Explain sex determination in humans with the help of class 12 biology CBSE

