A lens is made of flint glass (refractive index = 1.5). When the lens is immersed in a liquid of refractive index 1.25, focal length;
A. Increased by a factor of 1.25
B. Increased by factor of 2.5
C. Increased by factor of 1.2
D. Remains the same.
Answer
618k+ views
Hint: Material with a high index of refraction will have a shorter focal length than those with lower refractive indices. Let us take an example of lenses made of the synthetic polymers which is Lucite which is having a lower refractive index than glass which is leading to a slightly longer focal length.
Complete answer:
From the Lens maker formula,
$
\dfrac{1}{f} = (\mu - 1)\left( {\dfrac{1}{{{r_1}}} - \dfrac{1}{{{r_2}}}} \right) \\
\Rightarrow \dfrac{1}{{{f_a}}} = (1.5 - 1)\left( {\dfrac{1}{{{r_1}}} - \dfrac{1}{{{r_2}}}} \right) \\
\Rightarrow \dfrac{1}{{{f_1}}} = ({\mu _g} - 1)\left( {\dfrac{1}{{{r_1}}} - \dfrac{1}{{{r_2}}}} \right) \\
\Rightarrow {1_{ug}} = \dfrac{{{\mu _g}}}{{{\mu _1}}} = \dfrac{{1.5}}{{1.25}} = \dfrac{6}{5} \\
\Rightarrow \dfrac{1}{{{f_1}}} = \left( {\dfrac{6}{5} - 1} \right)\left( {\dfrac{1}{{{r_1}}} - \dfrac{1}{{{r_2}}}} \right) = \dfrac{1}{5}\left( {\dfrac{1}{{{r_1}}} - \dfrac{1}{{{r_2}}}} \right) \\
\Rightarrow \dfrac{{1/{f_a}}}{{1/{f_1}}} = \dfrac{{0.5}}{{1/5}} \\
\Rightarrow \dfrac{{{f_1}}}{{{f_a}}} = 0.5 \times 5 = 2.5 \\
\Rightarrow {f_1} = 2.5 \times {f_a} \\
$
Refractive index is said to be the velocity of light in a vacuum to its velocity in a specific medium. In other words it is also defined as the ratio of speed of light in a vacuum to the speed of light. Therefore if we talk about focal length then, the focal length of a lens is inversely proportional to refractive index of material of the lens medium. Moreover, the refractive index (m) increases focal length (f) of the lens decreases.
So, the correct answer is “Option B”.
Note:
There are two kinds of refractive index i-e refractive index from rarer medium and refractive index through denser medium and two types of refractive index : absolute refractive index and relative refractive index.
Complete answer:
From the Lens maker formula,
$
\dfrac{1}{f} = (\mu - 1)\left( {\dfrac{1}{{{r_1}}} - \dfrac{1}{{{r_2}}}} \right) \\
\Rightarrow \dfrac{1}{{{f_a}}} = (1.5 - 1)\left( {\dfrac{1}{{{r_1}}} - \dfrac{1}{{{r_2}}}} \right) \\
\Rightarrow \dfrac{1}{{{f_1}}} = ({\mu _g} - 1)\left( {\dfrac{1}{{{r_1}}} - \dfrac{1}{{{r_2}}}} \right) \\
\Rightarrow {1_{ug}} = \dfrac{{{\mu _g}}}{{{\mu _1}}} = \dfrac{{1.5}}{{1.25}} = \dfrac{6}{5} \\
\Rightarrow \dfrac{1}{{{f_1}}} = \left( {\dfrac{6}{5} - 1} \right)\left( {\dfrac{1}{{{r_1}}} - \dfrac{1}{{{r_2}}}} \right) = \dfrac{1}{5}\left( {\dfrac{1}{{{r_1}}} - \dfrac{1}{{{r_2}}}} \right) \\
\Rightarrow \dfrac{{1/{f_a}}}{{1/{f_1}}} = \dfrac{{0.5}}{{1/5}} \\
\Rightarrow \dfrac{{{f_1}}}{{{f_a}}} = 0.5 \times 5 = 2.5 \\
\Rightarrow {f_1} = 2.5 \times {f_a} \\
$
Refractive index is said to be the velocity of light in a vacuum to its velocity in a specific medium. In other words it is also defined as the ratio of speed of light in a vacuum to the speed of light. Therefore if we talk about focal length then, the focal length of a lens is inversely proportional to refractive index of material of the lens medium. Moreover, the refractive index (m) increases focal length (f) of the lens decreases.
So, the correct answer is “Option B”.
Note:
There are two kinds of refractive index i-e refractive index from rarer medium and refractive index through denser medium and two types of refractive index : absolute refractive index and relative refractive index.
Recently Updated Pages
Master Class 12 Economics: Engaging Questions & Answers for Success

Master Class 12 English: Engaging Questions & Answers for Success

Master Class 12 Social Science: Engaging Questions & Answers for Success

Master Class 12 Maths: Engaging Questions & Answers for Success

Master Class 12 Physics: Engaging Questions & Answers for Success

Master Class 9 General Knowledge: Engaging Questions & Answers for Success

Trending doubts
Which are the Top 10 Largest Countries of the World?

Draw a labelled sketch of the human eye class 12 physics CBSE

Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE

Why is the cell called the structural and functional class 12 biology CBSE

Draw ray diagrams each showing i myopic eye and ii class 12 physics CBSE

Which is the correct genotypic ratio of mendel dihybrid class 12 biology CBSE

