Question

A gas occupies \[600ml\] at \[{27^ \circ }C\] and \[730mm\] pressure. What would be its volume at STP?
A. $0.5244lit.$
B. $1.5244lit$
C. $2.5244lit$
D. $3.5244lit$

Answer 1

Hint: The combined gas law is simply the sum of the other gas laws. Furthermore, this law holds true when all variables are held constant except volume, pressure, and temperature. This law is based on temperature, pressure, and volume correlations.

Complete step by step solution:
The formula for the combined gas law can be tweaked to compare two sets of conditions in a single substance. The figures with subscripts of one in the equation reflect the beginning condition for temperature \[\left( T \right)\] , pressure \[\left( P \right)\] , and volume \[\left( V \right)\] . Those with two subscripts are also typical of the ultimate state.
In this question we are given;
Initial volume $\left( {{V_1}} \right) = 600mL$
Initial temperature $\left( {{T_1}} \right) = {27^ \circ }C = 273 + 27 = 300K$
Initial pressure $\left( {{P_1}} \right) = 730mm$
Now, we know that at STP the temperature $\left( {{T_2}} \right) = 273K$ and pressure $\left( {{P_2}} \right) = 760mm$ . So now, all we need to find out is the $\left( {{V_2}} \right)$ that is the final volume.
Using the combined gas law;
$\dfrac{{{P_1}{V_1}}}{{{T_1}}} = \dfrac{{{P_2}{V_2}}}{{{T_2}}}$
Putting all the given values in the equation we will find the final volume $\left( {{V_2}} \right)$
$
   \Rightarrow \dfrac{{730 \times 600}}{{300}} = \dfrac{{760 \times {V_2}}}{{273}} \\
   \Rightarrow {V_2} = 542.44mL = 0.5244L \\
 $
Therefore, volume at STP will be $0.5244lit.$
So, the correct option is: A. $0.5244lit.$

Note: It's worth noting that for calculation purposes, the temperature should always be expressed in kelvin. If the units are only available in Celsius, they must be converted to Kelvin. Furthermore, converting to kelvin is as simple as adding \[273\] to the specific measurement.