Question

A gas expands 0.25m³ at constant pressure 10³/m². The work done is
A. 250N
B. 250W
C. 250J
D. 2.5 erg .

Answer 1

Hint: In gas expansion, we assume ideal behaviour for the types of expansions, Isothermal expansion is when the gas expands with constant temperature. Adiabatic expansion don’t between the system and the surrounding and the temperature is no longer constant. If the pressure remains the offered expansion of gas, that is called isobaric expansion and The isotonic process is not involved with expansion of you because in this process the volume of the system remains the same. The work done is w=\[\int\limits_1^2 {pdv} \]

Complete step by step solution:
Work done in expansion
W = \[\int\limits_{}^{} {pdv} \]
     Where W= work done, P= pressure, V= Volume of the gas.
 Now \[\int\limits_{}^{} {pdv} \] = P∆V
Where, ∆V is the change in volume of the gas we are given that, the change in volume is
∆V= 0.25m³

And the constant pressure,
          P= 10³N/M3
∴From here, we can get the work done
          W = P∆V
          = 10³×0.25 \[\dfrac{{n\times{m^3}}}{{{m^2}}}\]
( ∴ N = \[\dfrac{{kg\times m}}{{{S^2}}}\], J= \[\dfrac{{kg\times{m^2}}}{{{S^2}}}\])
          = 250 \[\dfrac{{kg\times{m^4}}}{{{s^2}\times{m^2}}}\]
          =205 J
We know One in newton (N) is equal to one kg meter per second squared.
And one joule(J) is equal to one kg meter squared per second squared.

So the answer is (C) 250J

Note: The joule is derived from work or energy. It is equal to energy transferred to an object when a force of one newton acts on it in the direction of the force’s motion through a distance of one meter. And Newton is a unit of force.