Answer
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Hint: In order to solve this problem you need to calculate the food available for 1 man then calculate it for the men when 50 of them leave.
Complete step-by-step answer:
It is given that 300 men had food for 20 days.
Then if there is only 1 man then the food will last till 300x20 days = 6000 days.
So, when 50 men left the group the total men left was 300 – 50 = 250 men.
So, for the 250 men the food will last for $\dfrac{{6000}}{{250}} = 24$days.
So, for the 250 men the food will last for 24 days.
Note: In this problem you need to calculate the time available to consume food for 1 man. Then you can calculate it for 250 men. These problems always take care of the situation that sometimes when we calculate it for 1item then it will be less and sometimes it is more. Like if it would ask that if n number of men do this work in this number of days then the number of days will be lesser than that of n number of men, but here in case of food the number of days increases. So we have to take care when we have to divide and when to multiply.
Complete step-by-step answer:
It is given that 300 men had food for 20 days.
Then if there is only 1 man then the food will last till 300x20 days = 6000 days.
So, when 50 men left the group the total men left was 300 – 50 = 250 men.
So, for the 250 men the food will last for $\dfrac{{6000}}{{250}} = 24$days.
So, for the 250 men the food will last for 24 days.
Note: In this problem you need to calculate the time available to consume food for 1 man. Then you can calculate it for 250 men. These problems always take care of the situation that sometimes when we calculate it for 1item then it will be less and sometimes it is more. Like if it would ask that if n number of men do this work in this number of days then the number of days will be lesser than that of n number of men, but here in case of food the number of days increases. So we have to take care when we have to divide and when to multiply.
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