Questions & Answers

Question

Answers

Which manufacturer gained more profit?

A.${M_1}$

B.${M_2}$

C.${M_3}$

D.None

Answer
Verified

Hint- To solve the above question, we need to first calculate total profit gained by each machine. This can be done by finding the number of chairs/tables manufactured per week and then calculating the profit of each machine.

Complete step-by-step answer:

For machine ${M_1}$

From the table three chairs are manufactured per hour

Total time available per week =36

Total chair possible in one week

$ = \dfrac{{36}}{3} = 12$

Total table manufacture per hour=3

Total table possible in one week

$ = \dfrac{{36}}{3} = 12$

Therefore, the total profit per week is

$

= 12 \times 20 + 12 \times 30 \\

= Rs.600 \\

$

For machine ${M_2}$

From the table, five chairs are manufactured per hour

Total time available per week =50

Total chair possible in one week

$ = \dfrac{{50}}{5} = 10$

Total table manufacture per hour=2

Total table possible in one week

\[ = \dfrac{{50}}{2} = 25\]

Therefore, the total profit per week is

$

= 10 \times 20 + 25 \times 30 \\

= Rs.950 \\

$

For machine ${M_3}$

From the table two chairs are manufactured per hour

Total time available per week =60

Total chair possible in one week

$ = \dfrac{{60}}{2} = 30$

Total table manufacture per hour=6

Total table possible in one week

$ = \dfrac{{60}}{6} = 10$

Therefore, the total profit per week is

$

= 30 \times 20 + 10 \times 30 \\

= Rs.900 \\

$

Hence, the manufacturer used ${M_2}$ for production to maximize profit.

Note- These types of questions are statement based questions. In these types of questions read the statement carefully and gather all the information to form the given equation. After that, we start solving, in this question we have to calculate the profit of each machine per week. The maximum profit produced by the machine is our answer.

Complete step-by-step answer:

For machine ${M_1}$

From the table three chairs are manufactured per hour

Total time available per week =36

Total chair possible in one week

$ = \dfrac{{36}}{3} = 12$

Total table manufacture per hour=3

Total table possible in one week

$ = \dfrac{{36}}{3} = 12$

Therefore, the total profit per week is

$

= 12 \times 20 + 12 \times 30 \\

= Rs.600 \\

$

For machine ${M_2}$

From the table, five chairs are manufactured per hour

Total time available per week =50

Total chair possible in one week

$ = \dfrac{{50}}{5} = 10$

Total table manufacture per hour=2

Total table possible in one week

\[ = \dfrac{{50}}{2} = 25\]

Therefore, the total profit per week is

$

= 10 \times 20 + 25 \times 30 \\

= Rs.950 \\

$

For machine ${M_3}$

From the table two chairs are manufactured per hour

Total time available per week =60

Total chair possible in one week

$ = \dfrac{{60}}{2} = 30$

Total table manufacture per hour=6

Total table possible in one week

$ = \dfrac{{60}}{6} = 10$

Therefore, the total profit per week is

$

= 30 \times 20 + 10 \times 30 \\

= Rs.900 \\

$

Hence, the manufacturer used ${M_2}$ for production to maximize profit.

Note- These types of questions are statement based questions. In these types of questions read the statement carefully and gather all the information to form the given equation. After that, we start solving, in this question we have to calculate the profit of each machine per week. The maximum profit produced by the machine is our answer.

×

Sorry!, This page is not available for now to bookmark.