
A current of \[5A\] flows through a conductor. Calculate the number of electrons flowing through a conductor in\[2s\]. [Take charge of the electron as\[1.6 \times {10^{ - 19}}\]].
Answer
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Hint:The electrons move in a conductor like an electric current because they will be able to possess minimum electrical potential energy in the electric field which exists because of a battery or any other source. The electrons do move in a conductor when it is passing direct current but much more slowly than you might think. Calculate the number of electrons flowing through a conductor using the given method with the given data.
Complete step-by-step solution:
The electrons are repelled when a negative charge is brought near one end of a conductor. The movement of the electrons shift from one end to another end of the conductor when an electric voltage is applied. An electric field within the metal triggers then electrons will move toward the positive side.
Given:
Current \[I = 5A\]
Time \[t = 2s\]
Charge of the electron, \[e = 1.6 \times {10^{ - 19}}\]
To Find:
The number of electrons is \[n\].
\[ \Rightarrow \dfrac{{ne}}{t} = I\]
\[ \Rightarrow \dfrac{{n \times 1.6 \times {{10}^{ - 19}}}}{2} = 5\]
\[ \Rightarrow n = \dfrac{{10 \times {{10}^{20}}}}{{1.6}}\]
\[ \Rightarrow n = 6.25 \times {10^{19}}\]
\[\therefore \]The number of electrons is\[6.25 \times {10^{19}}\].
Note:The flow of electrons through a conductor, usually in the form of a wire is called electricity and this flow is called an electric current.
The current is defined as the power source that moves the existing electrons in the conductor around the circuit.
The electrons move through a wire from the negative end to the positive end.
The electrons' energy around the wire slows down the flow of electrons by the resistors.
Complete step-by-step solution:
The electrons are repelled when a negative charge is brought near one end of a conductor. The movement of the electrons shift from one end to another end of the conductor when an electric voltage is applied. An electric field within the metal triggers then electrons will move toward the positive side.
Given:
Current \[I = 5A\]
Time \[t = 2s\]
Charge of the electron, \[e = 1.6 \times {10^{ - 19}}\]
To Find:
The number of electrons is \[n\].
\[ \Rightarrow \dfrac{{ne}}{t} = I\]
\[ \Rightarrow \dfrac{{n \times 1.6 \times {{10}^{ - 19}}}}{2} = 5\]
\[ \Rightarrow n = \dfrac{{10 \times {{10}^{20}}}}{{1.6}}\]
\[ \Rightarrow n = 6.25 \times {10^{19}}\]
\[\therefore \]The number of electrons is\[6.25 \times {10^{19}}\].
Note:The flow of electrons through a conductor, usually in the form of a wire is called electricity and this flow is called an electric current.
The current is defined as the power source that moves the existing electrons in the conductor around the circuit.
The electrons move through a wire from the negative end to the positive end.
The electrons' energy around the wire slows down the flow of electrons by the resistors.
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