A common emitter amplifier has a voltage gain of 50, an input impedance of $\text{100 }\!\!\Omega\!\!\text{ }$ and an output impedance of $\text{200 }\!\!\Omega\!\!\text{ }$. The power gain of the amplifier is:
A. 100
B. 500
C. 1000
D. 1250
Answer
625.5k+ views
Hint: We must know that power gain of an amplifier is given as the ratio of output power to the input power. Also, power is given as the product of voltage and current. For a common emitter configuration, input will be through the base and output will be through the collector. We will also need ohm’s law to find the current gain.
Formula used:
$\begin{align}
& \text{Power Gain}=\dfrac{\text{Output Power}}{\text{Input Power}} \\
& P=VI \\
& I=\dfrac{V}{R} \\
\end{align}$
Complete answer:
Let us consider the voltage of the input as $V$ .
So, it is given that the voltage gain is 50. By voltage gain, we mean that it is the ratio of output voltage to the input voltage.
Now, to find the current gain, we will find the resistance gain and divide it with the voltage gain.
So, to find the resistance gain, the input impedance is given as $\text{100 }\!\!\Omega\!\!\text{ }$ and the output impedance is given as $\text{200 }\!\!\Omega\!\!\text{ }$.
Then, the resistance gain will be,
$\text{R=}\dfrac{\text{200 }\!\!\Omega\!\!\text{ }}{100\Omega }=2$
Now, we will find the current gain using ohm’s law. i.e.
$I=\dfrac{V}{R}$
Voltage gain is given as 50 and resistance gain is 2.
$\Rightarrow I=\dfrac{V}{R}=\dfrac{50}{2}=25$
Therefore, current gain is found to be 25.
Now, the power gain of the amplifier is given as,
$\text{Power Gain}=\dfrac{\text{Output Power}}{\text{Input Power}}$
But, we know $P=VI$.
Therefore,
\[\begin{align}
& \text{Power Gain = Voltage gain }\times \text{ Current Gain} \\
& \text{Power Gain }=\left( \dfrac{{{V}_{out}}}{{{V}_{in}}} \right)\times \left( \dfrac{{{I}_{out}}}{{{I}_{in}}} \right) \\
& \text{Power Gain }=50\times 25=1250 \\
\end{align}\]
Hence, the power gain of the amplifier is 1250.
So, the correct answer is “Option D”.
Note:
A Common Emitter Amplifier is mainly used because of the advantage of moderate current and voltage gain. A Common Emitter Amplifier is also used in frequency generation circuits in order to increase the strength of the input signal. In fans, motors and time circuits it is used to increase the speed.
Formula used:
$\begin{align}
& \text{Power Gain}=\dfrac{\text{Output Power}}{\text{Input Power}} \\
& P=VI \\
& I=\dfrac{V}{R} \\
\end{align}$
Complete answer:
Let us consider the voltage of the input as $V$ .
So, it is given that the voltage gain is 50. By voltage gain, we mean that it is the ratio of output voltage to the input voltage.
Now, to find the current gain, we will find the resistance gain and divide it with the voltage gain.
So, to find the resistance gain, the input impedance is given as $\text{100 }\!\!\Omega\!\!\text{ }$ and the output impedance is given as $\text{200 }\!\!\Omega\!\!\text{ }$.
Then, the resistance gain will be,
$\text{R=}\dfrac{\text{200 }\!\!\Omega\!\!\text{ }}{100\Omega }=2$
Now, we will find the current gain using ohm’s law. i.e.
$I=\dfrac{V}{R}$
Voltage gain is given as 50 and resistance gain is 2.
$\Rightarrow I=\dfrac{V}{R}=\dfrac{50}{2}=25$
Therefore, current gain is found to be 25.
Now, the power gain of the amplifier is given as,
$\text{Power Gain}=\dfrac{\text{Output Power}}{\text{Input Power}}$
But, we know $P=VI$.
Therefore,
\[\begin{align}
& \text{Power Gain = Voltage gain }\times \text{ Current Gain} \\
& \text{Power Gain }=\left( \dfrac{{{V}_{out}}}{{{V}_{in}}} \right)\times \left( \dfrac{{{I}_{out}}}{{{I}_{in}}} \right) \\
& \text{Power Gain }=50\times 25=1250 \\
\end{align}\]
Hence, the power gain of the amplifier is 1250.
So, the correct answer is “Option D”.
Note:
A Common Emitter Amplifier is mainly used because of the advantage of moderate current and voltage gain. A Common Emitter Amplifier is also used in frequency generation circuits in order to increase the strength of the input signal. In fans, motors and time circuits it is used to increase the speed.
Recently Updated Pages
Master Class 12 Business Studies: Engaging Questions & Answers for Success

Master Class 12 Chemistry: Engaging Questions & Answers for Success

Master Class 12 Biology: Engaging Questions & Answers for Success

Class 12 Question and Answer - Your Ultimate Solutions Guide

Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Social Science: Engaging Questions & Answers for Success

Trending doubts
The end of compass needle which points towards north class 12 physics CBSE

In order to find out the different types of gametes class 12 biology NEET_UG

Hormone responsible for the secretion of milk after class 12 biology CBSE

Yeast reproduces by A Spore formation B Multiple fission class 12 biology CBSE

Draw a well labelled diagram of LS of the human ki class 12 biology CBSE

Draw a diagram of a flower and name the parts class 12 biology ICSE

