Question

A coin is tossed twice, the probability of getting head both times is
A. $\dfrac{1}{2}$
B. $\dfrac{1}{4}$
C. $\dfrac{3}{4}$
D. 1

Answer 1

Hint: In order to solve this problem you need to know that probability is the number of favorable outcomes upon total number of outcomes and we also know that probability of getting heads and tails when a coin is tossed is always $\dfrac{1}{2}$. Using this information we will solve this problem.

Complete step-by-step answer:
When a coin is tossed twice then the number of outcomes can be:
[H,T],[T,H],[H,H],[T,T]
So, there are 4 outcomes and we can see that only one time there are both heads. So we can say the probability is $\dfrac{1}{4}$.
Hence the correct option is B.

Note: Whenever you face such types of problems of probability then you need to obtain the number of outcomes it can have then you have to use the formula number of favorable outcomes upon total number of outcomes. Proceeding in this way it will solve your problem.