Question

# A child has a die whose six faces show the letters as given belowA B C D E AThe die is thrown once. What is the probability of getting(a) A?(b) D?

Verified
156.6k+ views
Hint:If the die was thrown once, it has six possible outcomes- A, B, C, D, E. To find the probability of an event, we need to divide the number of favorable outcomes by the total number of all possible outcomes. Thus, probability of an event E is given by
$P(E)=\dfrac{n(E)}{n(S)}$
where,
n(E) is the number of favorable outcomes for event E to occur
n(S) is the total number of all possible outcomes (also called sample space)
For this experiment $n(S)=5$

\begin{align} & n(E)=2 \\ & P(E)=\dfrac{2}{5} \\ \end{align}
\begin{align} & n(E)=1 \\ & P(E)=\dfrac{1}{5} \\ \end{align}
Thus, answer for (a) is $\dfrac{2}{5}$ and for (b) is also $\dfrac{1}{5}$