Questions & Answers

Question

Answers

$\left[ h=6.62\times {{10}^{-34}}J-\sec \right]$

A. 0.25 kg

B. 0.15 kg

C. 0.2 kg

D. 0.1 kg

Answer
Verified

Where, $\lambda $is the wavelength, h is the plank constant, m is the mass of the body and v is the velocity .

- We are being provided with the value of wavelength $\lambda $ =$6.62\times {{10}^{-35}}m$

velocity is$100\text{ }m\text{ }{{\sec }^{-1}}$ and $\left[ h=6.62\times {{10}^{-34}}J-\sec \right]$

- We will find the mass of the body as x.

- As we know that de Broglie equation for wavelength is given by the formula $\lambda =\frac{h}{mv}$

So, by putting all the values given, in the formula we get:

$\begin{align}

& 6.62\times {{10}^{-35}}=\frac{6.62\times {{10}^{-34}}Js}{x\times 100} \\

& x=\frac{6.62\times {{10}^{-34}}}{6.62\times {{10}^{-35}}} \\

& x=0.1kg \\

\end{align}$

- It was de Broglie who found that the matter can also show the wave particle duality, just like the light. As light can behave like both of the particles and as a wave.

- And he also reasoned that matter would also follow the same equation for wavelength as light.

- We should not forget to write units after solving any question.

- We can say that de Broglie concept is most important, which is used to construct microscopes that are used in the measurement of objects of very small size.