Question

A bag of wheat weighs $200\,kg$ . To what height should it be raised so that its potential energy is $9800\,joule$ ( $g = 9.8\,m{s^{ - 2}}$ ):

Answer 1

Hint: In order to answer this question, first we will rewrite the given facts such as mass of a bag, potential energy and the gravitational constant. And then we will apply the formula of Potential Energy in terms of mass and height.

Complete step by step answer:
Given that: Mass of a bag of wheat, $m = 200kg$, potential energy is given, $P.E = 9800\,joule$, gravitational force, $g = 9.8m{s^{ - 2}}$, height, $h = ?$.So, here we will apply the concept and the formula of Potential energy in terms of mass and height of raising of the bag of wheat:

As we all know, an object's position can cause it to store energy. When a bow and arrow are drawn, the bow stores some energy, which is responsible for the kinetic energy gained when the bow is released. The energy possessed by an object as a result of its position in relation to other objects, internal tensions, electric charge, or other causes is known as potential energy. So, the using the formula of Potential Energy:
$P.E = m \times g \times h \\
\Rightarrow 9800 = 200 \times 9.8 \times h \\
\Rightarrow h = \dfrac{{9800}}{{200 \times 9.8}} \\
\Rightarrow h = 5\,m \\ $
Hence, from $5m$ of height should it be raised so that its potential energy is $9800\,joule$.

Note: As a result, potential energy is energy that has the potential to produce work in the future. The first scenario described objects that were all capable of generating energy.This potential energy must be stored in some way while it waits to execute this future job.