
A 12.5eV electron beam is used to bombard gaseous hydrogen at room temperature. What series of wavelengths will be emitted?
Answer
486k+ views
Hint: Due to the external energy from the beam, the hydrogen atom in the ground state gets excited to higher levels. The wavelength of the light emitted will depend on the energy differences of the levels of hydrogen atom.
Formula used:
The formula to obtain the wavelengths for the transitions between levels of hydrogen atom is given by:
$\dfrac{1}{\lambda}=R_H\left(\dfrac{1}{n^2}-\dfrac{1}{p^2}\right)$
Where, $R_H$ is Rydberg constant with a value of around $1.09\times10^{-7} m^{-1}$ for hydrogen atom.
Complete answer: or Complete step by step answer:
The nth energy level of a hydrogen atom has energy given by:
$E=\dfrac{-13.6}{n^2}$ eV
Therefore, the difference between the energies of two levels can be found with the help of this formula.
The difference between the energies of level n=1 and level n=2 is given as:
$E _2 –E_1=-13.6\left(\dfrac{1}{2^2}-\dfrac{1}{1^2}\right)=10.2$ eV
Similarly, difference between the energies of level n=3 and level n=1 is given as:
$E _3 –E_1=-13.6\left(\dfrac{1}{3^2}-\dfrac{1}{1^2}\right) \approx 12.09$eV
Thus, in the question, we are giving 12.5eV energy to the hydrogen atom. This amount of energy is sufficient to excite the hydrogen atom to level with n=3.
Thus, we will get 3 wavelengths corresponding to following transitions:
(i)n=3 to n=1.
(ii)n=3 to n=2.
(iii)n=2 to n=1.
: The formula to obtain the wavelengths for the transitions between levels of hydrogen atom is given by:
$\dfrac{1}{\lambda}=R_H\left(\dfrac{1}{n^2}-\dfrac{1}{p^2}\right)$
Where, $R_H$ is Rydberg constant with a value of around $1.09\times10^{-7} m^{-1}$ for hydrogen atom.
Using this formula, we may write:
(i)n=1 and p=3, gives us $\lambda$=103nm approximately.
(ii)n=2 and p=3, gives us $\lambda$=696nm approximately.
(iii)n=1 and p=2, gives us $\lambda$=122nm approximately.
Additional Information:
Transitions to level 2 from any level fall under Balmer series and transitions to level 1 from any level fall under Lyman series
Note:
The values of n and p upon switching might produce negative wavelengths here. There are 3 transitions in total but one might conclude 2 transitions ignoring the 3 to 2 transition.
Formula used:
The formula to obtain the wavelengths for the transitions between levels of hydrogen atom is given by:
$\dfrac{1}{\lambda}=R_H\left(\dfrac{1}{n^2}-\dfrac{1}{p^2}\right)$
Where, $R_H$ is Rydberg constant with a value of around $1.09\times10^{-7} m^{-1}$ for hydrogen atom.
Complete answer: or Complete step by step answer:
The nth energy level of a hydrogen atom has energy given by:
$E=\dfrac{-13.6}{n^2}$ eV
Therefore, the difference between the energies of two levels can be found with the help of this formula.
The difference between the energies of level n=1 and level n=2 is given as:
$E _2 –E_1=-13.6\left(\dfrac{1}{2^2}-\dfrac{1}{1^2}\right)=10.2$ eV
Similarly, difference between the energies of level n=3 and level n=1 is given as:
$E _3 –E_1=-13.6\left(\dfrac{1}{3^2}-\dfrac{1}{1^2}\right) \approx 12.09$eV
Thus, in the question, we are giving 12.5eV energy to the hydrogen atom. This amount of energy is sufficient to excite the hydrogen atom to level with n=3.
Thus, we will get 3 wavelengths corresponding to following transitions:
(i)n=3 to n=1.
(ii)n=3 to n=2.
(iii)n=2 to n=1.
: The formula to obtain the wavelengths for the transitions between levels of hydrogen atom is given by:
$\dfrac{1}{\lambda}=R_H\left(\dfrac{1}{n^2}-\dfrac{1}{p^2}\right)$
Where, $R_H$ is Rydberg constant with a value of around $1.09\times10^{-7} m^{-1}$ for hydrogen atom.
Using this formula, we may write:
(i)n=1 and p=3, gives us $\lambda$=103nm approximately.
(ii)n=2 and p=3, gives us $\lambda$=696nm approximately.
(iii)n=1 and p=2, gives us $\lambda$=122nm approximately.
Additional Information:
Transitions to level 2 from any level fall under Balmer series and transitions to level 1 from any level fall under Lyman series
Note:
The values of n and p upon switching might produce negative wavelengths here. There are 3 transitions in total but one might conclude 2 transitions ignoring the 3 to 2 transition.
Recently Updated Pages
Master Class 12 English: Engaging Questions & Answers for Success

Master Class 12 Business Studies: Engaging Questions & Answers for Success

Master Class 12 Social Science: Engaging Questions & Answers for Success

Master Class 12 Chemistry: Engaging Questions & Answers for Success

Class 12 Question and Answer - Your Ultimate Solutions Guide

Master Class 12 Economics: Engaging Questions & Answers for Success

Trending doubts
Which are the Top 10 Largest Countries of the World?

Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE

What is a transformer Explain the principle construction class 12 physics CBSE

Draw a labelled sketch of the human eye class 12 physics CBSE

What are the major means of transport Explain each class 12 social science CBSE

What is the Full Form of PVC, PET, HDPE, LDPE, PP and PS ?
