Courses
Courses for Kids
Free study material
Offline Centres
More
Store Icon
Store
seo-qna
SearchIcon
banner

How many 3 letter words can be formed using a, b, c, d, e if
A.repetition of letters is not allowed?
B.repetition of letters allowed?

Answer
VerifiedVerified
524.4k+ views
1 likes
like imagedislike image
Hint: In this question, we have to find the number of 3 letter words that can be formed using a, b, c, d, and e. If repetition is allowed then we can take that letter again. So, we have 5 intakes for every three places of 3 letter words.
seo images


Complete step-by-step answer:
The total number of words =5×5×5=125 . Now, if repetition is not allowed then we have to take only three letters out of 5 letters. The number of ways to select 3 letters out of 5 letters is 5C3 . But the letter can also be rearranged. The number of ways to rearrange 3 letters are 3! . The total number of 3 letter words is 5C3×3! .
Now, we have to find the number of 3 letter words if repetition is not allowed. That is we have to take 3 letters and we are given 5 letters. The number of 3 letter words that can be formed using 5 letters is 5C3 .
We know that words can be formed after rearranging also. So, the number of rearrangements is 3! .
Now, the total number of words that can be formed =5C3×3!=60 .
In case (ii), we have to find the number of three-letter words that can be formed if repetition is allowed. As repetition is allowed we can take that letter again if it is taken previously. In the first place, we can take a, b, c, d, and e. So, we have 5 intakes in the first place. Suppose, we take “a” in the first place of 3 letter words. We can also take the letter “a” in the second place too. So, in second place we can take a, b, c, d, and e. In the second place, we have 5 intakes. Similarly, in third place, we have 5 intakes.

The total number of words to be formed =5×5×5=125 .

Note: In this question, the mistake is generally done in finding the number of words that can be formed without repetition. As we have to take three letters out of five given letters, one can directly write 5C3 . But, the three words can rearrange also. So, we also have to think about the rearrangements.
Latest Vedantu courses for you
Grade 10 | MAHARASHTRABOARD | SCHOOL | English
Vedantu 10 Maharashtra Pro Lite (2025-26)
calendar iconAcademic year 2025-26
language iconENGLISH
book iconUnlimited access till final school exam
tick
School Full course for MAHARASHTRABOARD students
PhysicsPhysics
BiologyBiology
ChemistryChemistry
MathsMaths
₹36,600 (9% Off)
₹33,300 per year
Select and buy