
10 scooters, 5 motorcycles and 15 cars are parked in the parking area of a market. What is the probability that a scooter will leave the parking lot first?
Answer
496.5k+ views
Hint: Probability means possibility. Here, we are given that there are 10 scooters, 5 motorcycles and 15 cars in the parking area. And, we need to find the probability that the scooter leaves first. So, first we will add all the vehicles parked in the parking area.Next, we will find the probability that any vehicle leaves and from that we will find the probability of the scooter leaving first. Thus, calculating this, we will get the final output.
Complete step by step answer:
Given that, total number of scooters parked in the parking area = 10
Total number of motorcycles parked in the parking area = 5
Total number of cars parked in the parking area = 15
So, total number of vehicles parked in the parking area
\[\Rightarrow 10 + 5 + 15\]
\[\Rightarrow 30\]
Now, we need to find the probability that a scooter will leave the parking first as below:
The probability formula is defined as the probability of an event to happen is equal to the ratio of the number of favourable outcomes and the total number of outcomes.Probability of choosing any vehicles out the total number of vehicles is
\[\Rightarrow \left( {\dfrac{1}{{30}}} \right)\]
Next, the probability that the scooter will leave first is as follows:
Here, we have written this 10 times because there are 10 scooters given
\[\Rightarrow \left( {\dfrac{1}{{30}}} \right) + \left( {\dfrac{1}{{30}}} \right) + \left( {\dfrac{1}{{30}}} \right) + \left( {\dfrac{1}{{30}}} \right) + \left( {\dfrac{1}{{30}}} \right) + \left( {\dfrac{1}{{30}}} \right) + \left( {\dfrac{1}{{30}}} \right) + \left( {\dfrac{1}{{30}}} \right) + \left( {\dfrac{1}{{30}}} \right) + \left( {\dfrac{1}{{30}}} \right)\]
\[\Rightarrow \left( {\dfrac{{10}}{{30}}} \right)\]
\[\Rightarrow \left( {\dfrac{1}{3}} \right)\]
Hence, the probability that a scooter will leave the parking spot first is \[\left( {\dfrac{1}{3}} \right)\].
Note: A probability is basically the extent to which something is likely to happen. To find the probability of a single event to occur, first, we should know the total number of possible outcomes. Probability can range in from 0 to 1, where 0 means the event to be an impossible one and 1 indicates a certain event.
Complete step by step answer:
Given that, total number of scooters parked in the parking area = 10
Total number of motorcycles parked in the parking area = 5
Total number of cars parked in the parking area = 15
So, total number of vehicles parked in the parking area
\[\Rightarrow 10 + 5 + 15\]
\[\Rightarrow 30\]
Now, we need to find the probability that a scooter will leave the parking first as below:
The probability formula is defined as the probability of an event to happen is equal to the ratio of the number of favourable outcomes and the total number of outcomes.Probability of choosing any vehicles out the total number of vehicles is
\[\Rightarrow \left( {\dfrac{1}{{30}}} \right)\]
Next, the probability that the scooter will leave first is as follows:
Here, we have written this 10 times because there are 10 scooters given
\[\Rightarrow \left( {\dfrac{1}{{30}}} \right) + \left( {\dfrac{1}{{30}}} \right) + \left( {\dfrac{1}{{30}}} \right) + \left( {\dfrac{1}{{30}}} \right) + \left( {\dfrac{1}{{30}}} \right) + \left( {\dfrac{1}{{30}}} \right) + \left( {\dfrac{1}{{30}}} \right) + \left( {\dfrac{1}{{30}}} \right) + \left( {\dfrac{1}{{30}}} \right) + \left( {\dfrac{1}{{30}}} \right)\]
\[\Rightarrow \left( {\dfrac{{10}}{{30}}} \right)\]
\[\Rightarrow \left( {\dfrac{1}{3}} \right)\]
Hence, the probability that a scooter will leave the parking spot first is \[\left( {\dfrac{1}{3}} \right)\].
Note: A probability is basically the extent to which something is likely to happen. To find the probability of a single event to occur, first, we should know the total number of possible outcomes. Probability can range in from 0 to 1, where 0 means the event to be an impossible one and 1 indicates a certain event.
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