
0.0833 mol of carbohydrate of empirical formula \[C{{H}_{2}}O\] contains 1 g of hydrogen.
The molecular formula of carbohydrate is:
a.) \[{{C}_{5}}{{H}_{10}}{{O}_{5}}\]
b.) \[{{C}_{6}}{{H}_{12}}{{O}_{6}}\]
c.) \[{{C}_{12}}{{H}_{22}}{{O}_{11}}\]
d.) \[{{C}_{3}}{{H}_{4}}{{O}_{3}}\]
Answer
446.5k+ views
Hint: The general molecular formula of carbohydrates is \[{{(C{{H}_{2}}O)}_{n}}\] or \[{{C}_{n}}{{H}_{2n}}{{O}_{n}}\]. Means if carbohydrates contains n number of carbons and n number of oxygen atoms, then the carbohydrate contains 2n number of hydrogen atoms.
Complete step by step answer:
Molecular formulas are the multiples of empirical formulas.
In the question it is given that the number of given moles of the carbohydrate is 0.0833 mol.
One mole of carbohydrate contains 2n grams of hydrogens as per molecular formula of carbohydrates.
Therefore the number of hydrogen present in the given amount of carbohydrate = \[2n\times 0.0833g\]
In the question it is given that \[2n\times 0.0833g\] of carbohydrate contains one gram of hydrogen.
We can write the above data into a mathematical equation as follows.
\[2n\times 0.0833g = 1g\]
By solving the above mathematical expression we will get n = 6.
\[\begin{align}
& 2n\times 0.0833g=1g \\
& n=\dfrac{1}{2\times 0.0833} \\
& n=\dfrac{1}{0.166} \\
& n=6 \\
\end{align}\]
Therefore the molecular formula of given carbohydrate can be written as \[{{(C{{H}_{2}}O)}_{n}}\] = \[{{(C{{H}_{2}}O)}_{6}}\]=\[{{C}_{6}}{{H}_{12}}{{O}_{6}}\].
Thus the molecular formula of carbohydrate is \[{{C}_{6}}{{H}_{12}}{{O}_{6}}\].
So, the correct answer is “Option B”.
Note: Carbohydrates come under biomolecules containing Carbon, Hydrogen and Oxygen in their structures. Generally carbohydrates contain 1: 2 : 1 ratio of C : H : O. Means 1 mole of carbon, 2 moles of hydrogen and 1 mole of oxygen. There are four primary functions of carbohydrates in the human body. They generate energy, store the energy in the human body, prepare macromolecules, and additional protein and fat.
Complete step by step answer:
Molecular formulas are the multiples of empirical formulas.
In the question it is given that the number of given moles of the carbohydrate is 0.0833 mol.
One mole of carbohydrate contains 2n grams of hydrogens as per molecular formula of carbohydrates.
Therefore the number of hydrogen present in the given amount of carbohydrate = \[2n\times 0.0833g\]
In the question it is given that \[2n\times 0.0833g\] of carbohydrate contains one gram of hydrogen.
We can write the above data into a mathematical equation as follows.
\[2n\times 0.0833g = 1g\]
By solving the above mathematical expression we will get n = 6.
\[\begin{align}
& 2n\times 0.0833g=1g \\
& n=\dfrac{1}{2\times 0.0833} \\
& n=\dfrac{1}{0.166} \\
& n=6 \\
\end{align}\]
Therefore the molecular formula of given carbohydrate can be written as \[{{(C{{H}_{2}}O)}_{n}}\] = \[{{(C{{H}_{2}}O)}_{6}}\]=\[{{C}_{6}}{{H}_{12}}{{O}_{6}}\].
Thus the molecular formula of carbohydrate is \[{{C}_{6}}{{H}_{12}}{{O}_{6}}\].
So, the correct answer is “Option B”.
Note: Carbohydrates come under biomolecules containing Carbon, Hydrogen and Oxygen in their structures. Generally carbohydrates contain 1: 2 : 1 ratio of C : H : O. Means 1 mole of carbon, 2 moles of hydrogen and 1 mole of oxygen. There are four primary functions of carbohydrates in the human body. They generate energy, store the energy in the human body, prepare macromolecules, and additional protein and fat.
Recently Updated Pages
Earth rotates from West to east ATrue BFalse class 6 social science CBSE

The easternmost longitude of India is A 97circ 25E class 6 social science CBSE

Write the given sentence in the passive voice Ann cant class 6 CBSE

Convert 1 foot into meters A030 meter B03048 meter-class-6-maths-CBSE

What is the LCM of 30 and 40 class 6 maths CBSE

What is history A The science that tries to understand class 6 social science CBSE

Trending doubts
Father of Indian ecology is a Prof R Misra b GS Puri class 12 biology CBSE

Who is considered as the Father of Ecology in India class 12 biology CBSE

Enzymes with heme as prosthetic group are a Catalase class 12 biology CBSE

A deep narrow valley with steep sides formed as a result class 12 biology CBSE

An example of ex situ conservation is a Sacred grove class 12 biology CBSE

An orchid growing as an epiphyte on a mango tree is class 12 biology CBSE
