## Question Paper for Maharashtra SSC Board Class 10 Maths Paper-1 2018 - Free PDF Download

## FAQs on Maharashtra (MSBSHSE) SSC Board Question Paper Class 10 Maths Paper-1 - 2018

1. If the sum of zeroes of the quadratic polynomial $3x^2 – kx + 6$ is 3, then find the value of k.

Here a = 3, b = -k, c = 6

Sum of the zeroes,$\alpha +\beta=\dfrac{-b}{a}= 3$ (given)

$\Rightarrow \dfrac{−(−k)}{3} = 3$

$\Rightarrow k = 9$

2. Two cubes each of volume $27 cm^3$ are joined end to end to form a solid. Find the surface area of the resulting cuboid.

Volume of a cube $= 27 cm^3$

$\Rightarrow (side)^3=3^3$

$\therefore (side)=3$

Length of resulting cuboid, $l = 2 \times 3 = 6 cm$

Breadth of resulting cuboid, $b = 3 cm$

Height of resulting cuboid, $h = 3 cm$

Surface area of resulting cuboid $= 2(lb + bh + hl)$

$= 2(6 \times 3 + 3 \times 3 + 3 \times 6)$

$= 2(18 + 9 + 18) = 2(45) $

$= 90 cm^2$

3. Three distinct coins are tossed together. Find the probability of getting

(i) at least 2 heads

(ii) at most 2 heads.

Total number of possible outcomes $ = 2^3 = 8$

(HHH, TTT, HHT, THH, THT, HTH, TTH, HTT)

(i) Possible outcomes of at least two heads = 4

(HHT, THH, HHH, HTH)

$\therefore$ P(at least two heads)$ =\dfrac{ 4}{8}=\dfrac{1}{2}$

(ii) Possible outcomes of at most two heads = 7

(HHT, TTT, THH, THT, HTH, TTH, HTT)

$\therefore$ P(at most two heads) = $ \dfrac{7}{8}$

4. If the area of a circle is equal to sum of the areas of two circles of diameters 10 cm and 24 cm, calculate the diameter of the larger circle (in cm).

Let R be radius of larger circle and $r_1$, $r_2$ be radius of smaller circle.

So, as per question.

$\pi R^2 = \pi r_1^2 +\pi r_2^2 $

$\pi R^2 = \pi( r_1^2 + r_2^2 ) [ r_1 = \dfrac{10}{2} = 5cm, r_2 = \dfrac{24}{2} = 12 cm]$

$ R^2 =5^2 +12^2 $

$ R^2 =169$

$ R =13 cm$

So, Diameter $=2 \times R$

Diameter $=2 \times 13$

Diameter $=26 cm$

5. If the HCF of 408 and 1032 is expressible in the form 1032 × 2 + 408 × p, then find the value of p.

HCF of 408 and 1032 is 24.

$1032 \times 2 + 408 \times (p) = 24$

$408p = 24 – 2064$

$ p = -5$

6. From where we can download Maharashtra (MSBSHSE) SSC Board Question Paper Class 10 Maths Paper?

We can download Maharashtra (MSBSHSE) SSC Board Question Paper Class 10 Maths Paper from Vedantu site. Also, these are available offline in a bookstore.