RS Aggarwal Solutions Class 7 Chapter-12 Simple Interest (Ex 12B) Exercise 12.2 - Free PDF
FAQs on RS Aggarwal Solutions Class 7 Chapter-12 Simple Interest (Ex 12B) Exercise 12.2
1. How to Download the Solution of chapter 12 simple interest of RS Aggarwal class 7?
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2. Write down Formulas for finding Simple Interest in the period of a year, month and day
Like any other chapter of maths, chapter 12 simple interest also has a lot of formulas. Formulas that are used to find simple interest in various scenarios are written below
Formula to find simple interest on an amount after a certain period, when time is given in years.
Simple Interest (S.I.) = \[\frac{(P\times R\times T)}{100}\]
Formula to calculate the simple interest, when time is given in months
S.I. = \[\frac{(P\times R\times T)}{100\times 12}\]
Formula to find the simple interest, when time is provided in days
S.I. =\[ \frac{(P\times R\times T)}{100\times 365}\]
For a leap year formula changes a little 365 at the bottom becomes 366, only if the question specifies that the year is a leap year.
3. What are the two types of interests charged by financial institutions? Explain any one of them.
Interest on a capital amount charged by banks and other financial institutions is of two types. These two types of Interest are a) Simple Interest and b) Compound interest.
Simple Interest: Simple interest is calculated only on the original amount of capital, during a certain time with a specific interest rate. The formula to calculate simple interest is Simple Interest (S.I.) =\[ \frac{(P\times R\times T)}{100}\], where the P stands for original principal amount, R for interest rate and T for time passed.
4. Find simple interest and the resulting amount when a loan of 3500 is given for 219 days at an interest rate of 5% per annum.
A Loan of amount 3500 is given for a time period of exactly 219 days, with an interest rate of 5% p.a.
Here,
Principal (P) = Rs 3500
Intrest rate (R) = 5 % per annum
Time (T) = 219 days
The formula of finding simple interest, when time is given in days
Simple Interest = \[ \frac{(P\times R\times T)}{100\times 365}\] ,
or
= \[\frac{(3500\times 5\times 219)}{100\times 365}\] = \[\frac{( 35\times 219)}{73}\]=105
Hence the resulting amount will be = Principal amount + simple interest
= 3500 + 105
= 3605 rs Ans.
5. How many questions are there in exercise 12 A?
Chapter 12 Simple Interest of class 7 RS Aggarwal is divided into two exercises, Exercise 12 A and exercise 12 B and a test paper given at the end of the chapter. These exercises contain 25, 12 and 13 problems respectively. Exercise 12 B comprises 13 questions in total.
These questions target various aspects of Simple Interest. Questions in this chapter are of finding the final amount due after a certain period of time, with a specific interest rate. And problems finding the time required to collect a certain amount of simple interest on a specific principal amount with a fixed interest rate or calculating the principal amount, or the Interest rate, if everything else is given.