Answer

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**Hint:**We have 6 digits. We can make 6 digits numbers by giving each of the digits to each place in the 6-digit number.

**Complete step by step solution:**We have the digits 4, 5, 6, 0, 7 and 8. We can make 6-digit numbers by placing the given digits in each of the places of the six-digit number. We cannot put 0 in the ${1}^{\text{st}}$ place as it will make the number a 5-digit number.

We can write five numbers each with 6 digits as follows;

456078

560784

607845

784560

845607

**Additional information:**

The number of 6 digits numbers that can be formed using the given digits is given by,

\[{5 \times 5 \times 4 \times 3 \times 2 \times 1}\]

The ${1}^{\text{st}}$ digit can be any of the digits except 0. The 2nd place can have any of the other 5 digits not used in the ${1}^{\text{st}}$ place. Similarly, the ${3}^{\text{st}}$, ${4}^{\text{st}}$, ${5}^{\text{st}}$ and ${6}^{\text{st}}$ place have any 4, 3, 2 and 1 of the given digits respectively. So, the total number of 5-digit numbers that can be formed using the given digits is,

\[{5 \times 5 \times 4 \times 3 \times 2 \times 1 = 600}\]

**Note:**The answer need not be unique. We can form any 5 digits number by randomly placing the given digits. We must make sure that 0 does not come in the ${1}^{\text{st}}$ place. We use the concept of permutations to find the number of 6-digit numbers that can be formed using the given digits.

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