
y varies inversely with the square of x, given that\[y = \dfrac{1}{3}\] when $x = - 2$, express y in terms of x?
Answer
554.4k+ views
Hint: In the given question, we are required to find the value of a dependent variable such that the value of the independent variable is given to us. Here, in the given problem, we have y as the dependent variable and x as the dependent variable. There are mainly two types of relations between any two given variables: direct relation or direct proportion and inverse relation or inverse proportion.
Complete step by step solution:
In the given problem, we are required to express y in terms of x. A relation between both variables x and y is given to us and we are also told that y varies inversely with the square of x. So, we can deduce an inverse square proportionality from the above given statements.
So, $y \propto \dfrac{1}{{{x^2}}}$.
So, we can write \[y = k\dfrac{1}{{{x^2}}}\], where ‘k’ is a constant of proportionality.
Substituting the given values of y and x in above relation, to get the value of ‘k’.
$\dfrac{1}{3} = k\dfrac{1}{{{{( - 2)}^2}}}$
$ \Rightarrow k = \dfrac{4}{3}$
Thus, substituting the value of k and expressing y in terms of x, we get,
$y = \dfrac{4}{3}\left( {\dfrac{1}{{{x^2}}}} \right)$
$ \Rightarrow y = \dfrac{4}{{3{x^2}}}$
Note: In the question, we need to express a variable in terms of another variable with the help of a relation given to us. Such a variable whose value depends on another variable is called dependent variable and the variable whose value does not depend on any other parameter is called independent variable.
Complete step by step solution:
In the given problem, we are required to express y in terms of x. A relation between both variables x and y is given to us and we are also told that y varies inversely with the square of x. So, we can deduce an inverse square proportionality from the above given statements.
So, $y \propto \dfrac{1}{{{x^2}}}$.
So, we can write \[y = k\dfrac{1}{{{x^2}}}\], where ‘k’ is a constant of proportionality.
Substituting the given values of y and x in above relation, to get the value of ‘k’.
$\dfrac{1}{3} = k\dfrac{1}{{{{( - 2)}^2}}}$
$ \Rightarrow k = \dfrac{4}{3}$
Thus, substituting the value of k and expressing y in terms of x, we get,
$y = \dfrac{4}{3}\left( {\dfrac{1}{{{x^2}}}} \right)$
$ \Rightarrow y = \dfrac{4}{{3{x^2}}}$
Note: In the question, we need to express a variable in terms of another variable with the help of a relation given to us. Such a variable whose value depends on another variable is called dependent variable and the variable whose value does not depend on any other parameter is called independent variable.
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